*可以证明:n),m),m0),均是S及S的本征函数 4=0,S S小=+h7,Sn3=-h73),S2n0 n=0,S270=2h2n9,S2n2=2h73,S)=2h2n 其中,S.=S1+S +s 1=2 有交换对称性的自旋总波函数如下 单重态:S=0M,=0)m=[()1(2)-a(2) 90=a(1)a(2 三重态:S=1(M1=10-)129=()(2) 2(0)(9)(9)0/52 MS 三重态S=1 M 单重态S=0有交换对称性的自旋总波函数如下： (1 2 3 ) ( ) ( ) ˆ ˆ 2 * , , , s s s A z 可以证明：    均是S S 及 的本征函数 ( ) ( ( )) 2 2 2 2 1 2 1 2 1 2 1 2 1 2 1 2 ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ , 2 z z z x x y y z z 其中，S S S S S S S S S S S S S S = + = + = + + + + 2 2 2 2 2 2 2 (1 1 2 2 3 3 ) ( ) ( ) ( ) ( ) ( ) ˆ ˆ ˆ ˆ 0, 2 , 2 , 2 A S S S S S S S S S S        = = = = 单重态：S M = = 0 0 ( s ) 三重态：S M = = − 1 1,0, 1 ( s )      A = −   (1 2 2 1 2 ) ( ) ( ) ( )   ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 1 2 3 1 2 1 2 1 2 + 2 1 2 S S S             =    =  =      三重态 S =1 单重态 S = 0 1 MS = 0 MS = 1 MS = − 0 MS = (1 1 2 2 3 ) ( ) ( ) ( ) 2 ( ) ˆ ˆ ˆ ˆ 0, , , 0; z A z S S z S S S S S S S       = = + = − =