14-1拉普拉斯变换的定义 [f()]=(t)e-StdtF(S) S=o jo s为变量 关于积分下限0原函数 象函数 例￡K时Kesdt=5Ke-t=S ￡et时eedt=edt=S ￡[6(t=nδ()e-sdt-=0δ(t)dt=1 [ee-te-sdt =aast=训=sa S+a0- f £ [f(t)]=³ f(t)e–Stdt ' =F(S) –л䲀0࠶〟Ҿޣ ֻ 0- f £ [K]=³ Ke–Stdt = Ke–St –S 1 0- f = K S £ [G(t)]=³ G(t)e–Stdt 0- f =³ e –Stdt 0+ f = 1 S =³ G(t)dt 0- 0+ =1 £ [e–Dt ]=³ e –Dt e –Stdt 0- f ³ e –(D+S)tdt 0- f = e –(D+S)t –(S+D) 1 = 0- f S+D 1 = £ [ (t)]=³ (t)e–Stdt 0- f H H 14-1 ᣿Ფ᣿ᯥ਎ᦘⲺᇐѿ S=V + jZ sѪਈ䟿 ৏࠭ᮠ 䊑࠭ᮠ