(3)令月=kn1+k2y2+a3,且B与B2,B正交得 √2 k1=-%1,a3]=“,k2=-[y2,O2] 6 故3=( 1) 333 B3 √3√3√3√3 →y3Np 66623 1 1 2 2 3 3 2 1 1 1 3 2 2 2 T 3 3 T 3 3 (3) , 2 6 [ , ] , [ , ] 2 6 111 ( 1) 333 3333 ( ) 6 6 6 2 k k k k                = + + = − = = − = = −  = = − 令 且 与 , 正交得 故