sin= 1F(12 0<z|<0 (2k+) (-1)=2 0→可去奇点 (2k+ 注意:①:z=b为奇点,f(在b点不可导 (k k ②b为可去奇点的充要条件 i>f(=)=∑C(=-b)i>lm(=)=有限( ) ( ) < < ¥ + - = å ¥ = + z k z z z z k k k ,0 2 1 ! sin 1 1 0 2 1 ( ) ( ) \ = ® 可去奇点 + - = å ¥ = 0 2 1 ! 1 0 2 z k z k k k 注意：① Q z = b为奇点 , f (z)在b点不可导 ( ) ( ) k! f b C k k ¹ ②b为可去奇点的充要条件 > ( ) = ( - ) Û > ( ) = 有限 ® ¥ = -¥ i f z å C z b ii f z z b k k k lim