⑩天掌 Teaching Plan on Advanced Mathematics o 由条件y==3,得C1=3, 所以 y=3(+x2) 两端再积分,得 y=x+3x+ C2 又由条件=1,得C2=1 于是所求得特解为 y=x+3x+1 tianjin polytechnic dmivendityTianjin Polytechnic University Teaching Plan on Advanced Mathematics 由条件y  x=0 = 3,得 3, C1 = 所以 3(1 ). 2 y  = + x 两端再积分，得 2 3 y = x + 3x +C 又由条件y x=0 = 1,得 1, C2 = 于是所求得特解为 3 1 3 y = x + x +