x2 sint 1sint f(r) dt,∫(1) dt=0, sIn 2sin x ∫(x)=-2·2x= b(x)1 f(1) x f(x)dx 0 2xsinxdx sinx dx 2 2 cos x (cos1-1)0, sin (1) 1 1 = dt = t t f  = 2 1 , sin ( ) x dt t t  f x , 2sin 2 sin ( ) 2 2 2 x x x x x f  x =  =  1 0 xf (x)dx (1) 2 1 = f  −  1 0 2 ( ) 2 1 x f x dx  = − 1 0 2 2 sin 2 1 x x dx  = − 1 0 2 2 sin 2 1 x dx   1 0 2 cos 2 1 = x (cos1 1). 2 1 = −