例2.用 Euler公式的预测—校正系统求解例1 解:由(10)式,有 Euler lm 2 2×0. )=1+0.1(1 )=1.1 y1=+h(1-2x)=1+01(.1-2×01)=1.098 1.1 2x 2×0.1 y2=y1+h(y1--)=10918+0.1(1.0918 )=11827 1.0918 2x 2×0.2 y2=y1+h(y2 )=1.09180.1(1.1827 )=1.1763 1.1827例2. 用Euler公式的预测— — 校正系统求解例1. 解: 由(10)式,有 ) 2 ( 0 0 1 0 0 y x y = y + h y - ) 1.1 1 2 0 1 0.1(1 = ´ = + - ) 2 ( 1 1 1 0 1 y x y = y + h y - ) 1.0918 1.1 2 0.1 1 0.1(1.1 = ´ = + - ) 2 ( 1 1 2 1 1 y x y = y + h y - ) 1.1827 1.0918 2 0.1 1.0918 0.1(1.0918 = ´ = + - ) 2 ( 2 2 2 1 2 y x y = y + h y - ) 1.1763 1.1827 2 0.2 1.0918 0.1(1.1827 = ´ = + - Euler1.m