∫八o(x)(xk=」mx)1(x)=J()m=F()+C=F(x)+C 例1∫2cos2x=eo2x(2x)=Jcos2xd(2x) cosudu=sinu+c=sin 2x+c 例2 3+2x (3+2x)dx=2!3+2 d(3+2x) 3+2x x In Ju+C=nIn 3+2x +C 例3∫2x2k=Je(x2)ak=Jed(x2)=Jeht el +c=er+c 积分表 首页上页返回 页结束铃积分表 首页 上页 返回 下页 结束 铃    f[j(x) ]j(x)dx= f[j(x) ]dj(x)= f (u)du=F(u)+C=F[j(x) ]+C 例 1    例1 2cos2xdx= cos2x(2x)dx= cos2xd(2x) =  cosudu =sinu+C =sin 2x+C  例 2    + + +  = + = + (3 2 ) 3 2 1 2 1 (3 2 ) 3 2 1 2 1 3 2 1 d x x x dx x dx x 例2 dx u C u = = +  ln | | 2 1 1 2 1 = ln |3+2x|+C 2 1  例 3     xe dx = e x dx = e d x = e du x x x u 2 ( ) ( ) 2 2 例 2 2 2 3 e C e C u x = + = + 2  例 1    例 1 2cos2xdx= cos2x(2x)dx= cos2xd(2x)    2cos2xdx= cos2x(2x)dx= cos2xd(2x) =  cosudu = sinu + C =sin 2x+C   cos sin =sin 2x+C  例 2    + + +  = + = + (3 2 ) 3 2 1 2 1 (3 2 ) 3 2 1 2 1 3 2 1 d x x x dx x dx x 例 2    + + +  = + = + (3 2 ) 3 2 1 2 1 (3 2 ) 3 2 1 2 1 3 2 1 d x x x dx x dx x dx u C u = = +  ln | | 2 1 1 2 1 = ln |3+2x|+C 2 1 dx u C  u = = +  ln | | 2 1 1 2 1 = ln |3+2x|+C 2 1  例 3     xe dx = e x dx = e d x = e du x x x u 2 ( ) ( ) 2 2 2 2 2 例 3     xe dx = e x dx = e d x = e du x x x u 2 ( ) ( ) 2 2 2 2 2 例 3     xe dx = e x dx = e d x = e du x x x u 2 ( ) ( ) 2 2 2 2 2 e C e C u x = + = + 2  下页