02-01-05一级考试选择题(H) 1、我们通常所使用的微型计算机是属于() A)模拟计算机B)特殊计算机C)数字计算机D)混合计算机 2、既能向主机输入数据又能接收由主机输出数据的设备是() A)CD-ROMB)显示器C)调制解调器D)鼠标 3、()是用于提高内存储器的访问效率的高速缓冲存储器。 A) RAM B) ROM C) CACHE D)ALU

02-01-05一级考试选择题(G) 1、在计算机上播放VCD采用的是() A)人工智能B)网络技术C)多媒体技术D)数据库技术 2、下列访问速度最快的是() A)硬盘B)光驱C)内存D)寄存器 3、用户可用的内存是在()中。 A)ROM B)RAM c)RoM和RAM D)硬盘

1 Induction Recall the principle of induction: Principle of Induction. Let P(n) be a predicate. If ·P(0) is true,an for all nE N, P(n) implies P(n+1), then P(n) is true for all nE N As an example let's try to find a simple expression equal to the following sum and then use induction to prove our guess correct 1·2+2·3+3:4+…+n·(mn+1) To help find an equivalent expression, we could try evaluating the sum for some small n and(with the help of a computer) some larger n sum

1 Logic A proposition is a statement that is either true or false. Propositions can be joined by \and\, \or\, \not\, \implies\, or \if and only if\. For each of these connective, the defini- tion and notational shorthand are given in the table below. Here A and B denote arbitrary propositions

1 Case analysis The proof of a statement can sometimes be broken down into can be tackled individually 1.1 The method In order to prove a proposition P using case analysis Write, We use case analysis Identify a sequence of conditions, at least one of which must hold. (If this is not obvious, you must prove it

一、示例程序 main() int a, b,c; scanf(\%/od, %d\, &a, &b); c=a

02-01-05一级考试选择题(B) 1、智能机器人不属于计算机在()方面的应用。 A)科学计算B)计算机辅助制造C)过程控制D)人工智能 2、运算器中的运算结果可直接传送到() A)RAMB)软盘C)ROMD)硬盘 3、对软盘进行全面格式化后() A)就不能往软盘上写数据 B)软盘中原有的数据将全部丢失 C)软盘中原有的数据将部分丢失 D)软盘就不会感染计算机病毒 4、键入计算机的汉字需要转换成机内的统一()

Diffusion: Read Plummer Chap. 7, sections 7.1-7.4,, 7.53, 7.5.8 Show that c(zt) Wroexpfzla)I,with a=2VDf, is a solution to Fick's second law of diffusion. ac(z, t) dc(zt) 2. a) What is the intrinsic carrier concentration in Si at 1100 C? b) Calculate the effective diffusivity (including first-order, charged-vacancy corrections)for As impurities in Si at 1100 C for two cases: 1)CAs=10 cm and ii)

1)Plot resolution and depth of field as a function of exposure wavelength for a projection aligner with 100nm