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1.H2S和CO2组成的气体混合物中,H2S的摩尔分数为0.513。将 1750cm3(在21℃,101.325kPa下测得的)混合气体通入350℃的管 式炉,然后迅速冷却。使流出来的气体通过盛有无水氯化钙的管子,结 果管子的质量增加了34.7mg。试求350℃时反应 HS(g)+CO, (g)=COS(8)+H,o(g) 的标准平衡常数。设气体服从理想气体状态方程
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1.25℃,101325Pa时NaCl(B)溶于1kgH2OA)中所成溶液的v 与nB的关系为:=10038+16.6253(nB/mo)+1.7738(mB/mol) 0.1194(n/mo)2]cm3。(1)求H2O和NaC的偏摩尔体积与mB的关系
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一、臭氧的基本知识 1、什么是臭氧? 臭氧又称富氧、三子氧、超氧。雷电过後,有时人们可以闻到它的 气味。臭氧在常温下可以自行还原为氧气。臭氧是氧的同素异形体,分 子式为O3,是一种较为不稳定的、活泼的气体。大气中少量的臭氧可 在某些自然和人为的条件下产生,包括:闪电,日光对烟雾成分的作用, 有故障的电灯开关和电机刷,高压输电线路,复印机,核辐射,紫外灯 以及水电解等等
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标准I/O涵数库中公共函数包含于 stdio.h头文件中,使用时先引用# inlude stdio h编译命令
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第一节光合作用 生物按其利用碳源的类型可分为两类:(1)自 养生物( autotrophs),即能够吸收和利用CO,或 无机碳化物,合成自身所需的全部有机物的生物 例如绿色植物、藻类、硫细菌等。这类生物利 用的供氢体也是无机的,如H2O、H2S等
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6.001 Structure and Interpretation of Computer Programs. Copyright o 2004 by Massachusetts Institute of Technology 6.001 Notes: Section 31.1 Slide 3l.ll Trees, graphs and Search In previous lectures we have seen a number of important themes, which relate to designing code for complex syste
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6.001 Structure and Interpretation of Computer Programs. Copyright o 2004 by Massachusetts Institute of Technology 6.001 Notes: Section 11.1 Slide ll1.1 Elements of a Data Abstraction For the past few lectures, we have been exploring the topic of data abstractions, and their role in modularizing complex
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6.001 Structure and Interpretation of Computer Programs. Copyright o 2004 by Massachusetts Institute of Technology 6.001 Notes: Section 9.1 Slide 9.1.1 Manipulating complex numbers In the last lecture, we introduced symbols into our language
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6.001 Structure and Interpretation of Computer Programs. Copyright o 2004 by Massachusetts Institute of Technology 6.001 Notes: Section 30.1 Slide 30l1 In this lecture, we are going to go back to several themes that 6.001: Structure and Interpretation of we have been exploring over the past few weeks, and stitch
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6.001 Structure and Interpretation of Computer Programs. Copyright o 2004 by Massachusetts Institute of Technology 6.001 Notes: Section 6.1 Slide 6.1.1 Types When we first starting talking about Scheme expressions, you may recall we said that(almost )every Scheme expression had
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