点击切换搜索课件文库搜索结果(708)
文档格式:PDF 文档大小:202.94KB 文档页数:86
1 Codes: C: complete (>80%); P: partial (50-80%); S: small (<50%); V: variable (approximate percentage when known); R: recovered but no quantitative information available; NR: not recovered
文档格式:DOC 文档大小:161.5KB 文档页数:5
1.(补充习题)判断以下公式对是否可合一若可合一,则求出最一般的合一 (3)P(f(x),y),P(y,f(b)) 解:令O=,S={p(f(x),y),P(y,f(b))} ①差异集为{f(x),y},做替换{f(x)/y},则 1=0of(x)y}={f(x)/y} S1 =S, ={P((x), f (x), P( f(x),(b)); ②差异集为{x,b},做替换{b/x},则
文档格式:PDF 文档大小:1.85MB 文档页数:39
Definitions of Modeling and simulation physics-based modeling empirical modelIng Model/simulation Development Process module identification module ordering: DSM,'s and N2 diagrams module coding fidelity and benchmarking model execution simulation Computational Issues
文档格式:PPT 文档大小:277KB 文档页数:23
电机转速公式: n=(1-s)n0=60(1-s)f /p 其中 s—转差率; n0—同步转速;
文档格式:PDF 文档大小:2.83MB 文档页数:21
ECTURE +2 RIGId BoDY DYNAnIC 工Ap1CAT105FA。R工 GENERAL ROTATIONAL JYNMICS EULER'S EQuATIoN of MOTIoN TORQVE fREE SPECIAL CAsEs PRIMARY LESSONS 3D RoTATONAL MOTION MUCH MORE COMPLEX
文档格式:PPT 文档大小:48.5KB 文档页数:4
例 3-17 某溶液中含Zn2+ 、Cd2+两种离子,其浓度分别为C(Zn2+ ) = 2.93×10-5 mol•dm-3 ,C(Cd2+ ) = 1.40×10-6 mol•dm-3。向该溶液中不断 通入H2S,使溶液中H2S保持饱和(H2S的饱和浓度为0.10 mol•dm-3 )
文档格式:PDF 文档大小:528.88KB 文档页数:4
Solubility limit for P at 1273 K is Co 2 1 x 10 cm\. Intrinsic carrier concentration is 10 cm\. Thus, before including higher order terms, Do=13x10-4 cm2/s. But with first order and second order correction terms
文档格式:PDF 文档大小:1.03MB 文档页数:205
Part 1 What’s the Issue? Part 2 The Traps Part 3 An Interlude: Globalization to the Rescue? Part 4 The Instruments Part 5 The Struggle for the Bottom Billion
文档格式:PPTX 文档大小:22.4MB 文档页数:33
《近代中国对外关系史 The History of Modern China's Foreign Relations》课程教学资源(PPT讲稿)Week 3 - The First Opium War and the Treaty of Nanking
文档格式:PDF 文档大小:909.04KB 文档页数:73
上海交通大学:《Design and Manufacturing》课程教学资源(参考文献)Shigley's Mechanical Engineering Design ch3 Load and stress analysis
首页上页1415161718192021下页末页
热门关键字
搜索一下,找到相关课件或文库资源 708 个  
©2008-现在 cucdc.com 高等教育资讯网 版权所有