Eco514 Game Theory Signaling Games Marciano Siniscalchi January 10, 2000 Introduction Signaling games are used to model the following situation: Player 1, the Sender, receives some private information and sends a message m E M to Player 2, the Receiver. The latter, in turn, observes m but not 0, and

典型习题解析 1图示直杆截面为正方形,边长a=200m,杆长L=4m,F=10k,材料密度 p=20k/m3.考虑杆的自重,计算1-1和2-2截面轴力,并画轴力图

1、深入理解横截面上内力的概念内力分量对应的基本变形掌握根据变形规定的内力正负号规则。 2、熟练掌握由截面法导出的由截面一侧外力求指定截面上的F、Mx、FQ、M的方法(截面一侧外力法)以及由M(x)Fo(x)、q(x)的积分关系,求指定截面上FQ、M的面积法。 3、了解控制面的概念,熟练掌握基于平衡微分方程非无限接近两相邻控制面间内力图变化规律以及无限接近两控制面间内力图突变的规律

第一章流体流动 【例1-1】已知硫酸与水的密度分别为1830kg/m3与998kg/m3,试求含硫酸为60%( 量)的硫酸水溶液的密度为若干。 解:根据式1-4 10.604 1830998 =(3.28+4.01)10-4=7.29×10-4 Pm=1372kg/m3 【例1-2】已知干空气的组成为:O21%、N278%和Ar1%(均为体积%),试求干空气在 压力为9.81×10Pa及温度为100℃时的密度

一、泵前中格栅 1.设计参数: 设计流量Q=2.6×104m3/d=301L/s 栅前流速v1=0.7m/s,过栅流速v2=0.9m/s

第一章 1.1证明:1°由数学期望的定义,且X是非负随机变量,有:E(N)=nonp(n=n=1P(nn),令m=n-1,有:E(N)=np(nn)=mpnm+1)=2m=p(n>m)=n-p(n>n)2°先证明一般情况。由数学期望的定义,且X是非负随机变量,有:E(Xn)=)= Jntn-I- dt dF)

第十三章动量矩定理 13.1已知质量为m的质点运动方程为x= coswt,y= b sin2@ 求质点对原点O的动量矩

Due Sept 17. 2002 1. a) Mean free path 2= kBI d-p where k=1.38×102,T=293K,p=10mTor=133Pa,d=1A=100m 38×10-3(293 6.9cm ford=1A Jr(m)(332)017mfrd=2A b) Use the ideal gas law pV=nkB T 1.33Pa vk7(138×102X90)33×10m-33×10cm3

Reading Assignment: Kinetics, Vac. Tech: Campbell, 10.1-1. 4(or Ohring Ch 2) 1. Consider a vacuum system at room temperature that has been pumped down to a 10 m-Torr with mostly nitrogen as determined from the residual gas analyzer. Make an in

Background SDM split-summer format M Heavily front-loaded Systems perspective Concern with scaling Product development track, CIPD Place in wider context of product realization Joint 16(Aero/Astro)and 2(Mech E) Robust system design