一、选择题:(20分)将答案号填入下表 题号12345678910 答案号 1.以下说法错误的是: (A)摩尔吸光系数K随浓度增大而增大(B)吸光度A随浓度增大而增大 (C)透射比T随浓度增大而减小 (D)透射比T随比色皿加厚而减小

外研版（三起）（2012）小学英语五年级下册Module 9 Unit 2 Mum bought new T-shirts for you.Module 9 Unit 2 Mum bought new T-shirts for you.课件(9)

1一飞轮半径为0.2m、转速为 150rmin-1,因受制动而均匀减速,经 30s停止转动.试求:(1)角加速度和 在此时间内飞轮所转的圈数;(2)制动 开始后t=6s时飞轮的角速度;(3)t= 6s时飞轮边缘上一点的线速度、切向 加速度和法向加速度

A1, A,----two arbitrary constants S S2----real numbers or conjugate complex Since the s,t and s,t must be dimensionless, S,, S2----(1/s)

8.4多元复合函数的求导法则 设z=f(u,v),而u=(t),v=y(t),如何求? 设z=f(v),而u=(,y)v=y(,y),如何求和

1某种电动机启动后转速随时间变化 的关系为a=a-e),式中o=9.0rad-s, t=2.0s.求:(1)t=6.0s时的转速;(2)角加 速度随时间变化的规律;(3)启动后内6.0s 转过的圈数

Chapter 15: Temperature and the Ideal Gas Law了解) 1.平衡态(thermal equilibrium) 2. The Zeroth Law of Thermodynamics If two systems are in thermal equilibriu with a third system, then they are in thermal equilibrium with each other. 3.系统平衡态的宏观状态参量 Equation of state, equilibrium states 4. Absolute Temperature (Kelvin scale) T=273.15+t

外研版（三起）（2012）小学英语六年级下册Module 7 Unit 2 She couldn't see or hear.Module 7 Unit 2 She couldn't see or hear.课件(4)

例1一飞轮半径为0.2m、转速为150rmin-1,因 受制动而均匀减速,经30s停止转动.试求:(1) 角加速度和在此时间内飞轮所转的圈数;(2)制动开 始后t=6s时飞轮的角速度;(3)t=6s时飞轮边缘 上一点的线速度、切向加速度和法向加速度

萃取、冲洗和干燥:还没到结束不能算结束。藉由分液漏斗示 。 范液相-液相萃取并学习如何用”反应检查步骤”检查你的反应。这 是一个你不会想错失的一个纯化技巧! Extracting, Washing and Drying: It ain't over 'til it's over. Learn how to \work up\ your reaction using a separatory funnel to perform a liquid-liquid extraction. This is one purification technique you don't want to miss!