1设E是直线上的一有界集,mE>0,则对任意小 于mE的正数,恒有子集E1,使m*E1=c 证明:由于E有界,故不妨令EC[a,b 令f(x)=m*(en[a,x),则f(a)0,f(b)=m*E 下证f(x)在[a,b]上连续

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Directions: In this part, you will hear ten short statements. The statements will be spoken only once. After each statement, there will be a pause. During the pause, you must read four choices marked A, B, C, and D, and decide which is the best answer. Then mark the corresponding letter on the Answer sheet with a single line through the center

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定理3(函数极限的局部保号性) 如果f(x)→A(x→x),而且A>0(或A0(或f(x)0的情形证明

外研版（三起）（2012）小学英语五年级下册Module 9 Unit 1 We laughed a lot.Module 9 Unit 1 We laughed a lot.课件(4)

定理3(收敛数列的保号性) 如果数列{xn}收敛于a,且a>0(或aN时,有xn>0(或x0的情形证明. 由数列极限的定义,对ε=>0,3NN,当n>N时,有