定理7.3.1设矩阵A∈Rn,且非奇异,则一定存在正交矩 nxn 阵,上三角矩阵R,使 A=OR (7.3.2) 且当要求R的主对角元素均为正数时,则分解式(7.3.2)是唯一的。 证明存在性有矩阵A的非奇 Householder异性及变换矩 阵的性质(3)知,一定可构造n-1个H矩阵:H1,H2,…,Hn-1使 A+1=HA(k=1,2,…n-1)

1.设A∈R且有线性初等因子,其特征值为2n证明:存在A的左特征向量 yy2y和右特征向量xx2xn,满足A=xy 2.设A∈R且有线性初等因子,其特征值为2,,相应的左特征向量为yy2y ,右特征向量为xx2xn,并有y,x,=0(i≠),y,x,≠0.证明:矩阵

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