1. 聚氯乙烯（Polyvinyl chloride-PVC） 2. 聚乙烯（Polyethylene-PE） 3. 聚丙烯（Polypropylene-PP） 4. 聚苯乙烯（Polystyrene-PS） 聚甲基丙烯酸甲酯 (Polymethyl methacrylate-PMMA) 聚酰胺（Polyamide-PA） 聚甲醛（Polyoxymethylene-POM） 聚碳酸酯（Polycarbonate-PC） 常用的热固性塑料酚醛树脂（PF） 常用橡胶 通用合成纤维 聚酯纤维

心脏解剖 先天性心脏病的外科治疗 surgical treatment of congenital heart disease 动脉导管未闭 Patent Ductus Arteriosus(PDA) 房间隔缺损 atrial septal defect(ASD) 室间隔缺损 Ventricular septal defect(VSD) 肺动脉口狭窄 Pulmonary stenosis(PS) 主动脉狭窄 Coarctation of aorta 主动脉窦动脉瘤破裂 Rupture of aortic sinus aneurysm 法洛四联症 Tetralogy of Fallot(TOF) 后天性心脏病的外科治疗 慢性缩窄性心包炎 Chronic constrictive pericarditis 二尖瓣关闭不全 Mitral insufficiency(MI) 二尖瓣狭窄 Mitrol stenosis(MS) 主动脉瓣狭窄 Aortic Stenosis(AS) 主动脉瓣关闭不全 Aortic insufficiency(AI) 冠状动脉粥样硬化性心脏病 Atherosclerotic coronary artery disease(CAD) 心脏粘液瘤 Cardiac myxoma(CM) 胸主动脉瘤

REMINDER: Quiz #2 will be held from 7: 30-9: 30 p. m. Thursday, November 13 in Walker Memorial. The quiz will cover materials in Chapters 4-7(through Section 7. 4)of O&w, Lectures and Recitations through October 29, Problem Sets #4-6, and that part of Problem Set 7 involving problems from Chapter 7 Reading Assignments

Problem set SolutioN Exercise for home study o&W8.35 (a) From the system diagram, we see that a(t)=a(t)cos(wet) Using the multiplication property ZGu)= o(X(u)* FT(cos wct)) FT of cos wt is two impulses with area T at +wc. Therefore, Z(w)is the spectrum

The lowpass filter H(u) has a cutoff frequency wc=205T rad/ sec. Thus, c(t)is r(t) where all terms with frequency above we are removed by the lowpass filter. The terms which are kept have kwol 205T rad /sec k|< 10.25, so the output, ac(t),is r(t)= To obtain n, we sample c(t) every T=5 10-3 seconds with an impulse train The sampling frequency is 400T=2 x maximum frequency in c(t). Therefore

REMINDER: Quiz 1 will be held from 7: 30 to 9: 30 p. m. Tuesday, October 14 The quiz will cover material in Chapters 1-3 of o&w Lectures and Recitations through september 26, Problem Sets 1-3 and that part of Problem Set 4 involving problems from Chapter 3 Reading assignments

REMINDER: Computer Lab #1 is due on October 8 REMINDER: Quiz 1 will be held from 7: 30-9: 30 p. m. Tuesday, October 14 in Walker Memorial. The quiz will cover material in Chapters 1-3 of o W, Lectures and Recitations

Ps:细写字母为修改后噶答案,具体位置见红色处 毛邓三学习指导书——选择题答案 第258页:(社会主义初级阶段理论) (一)1~5: DDaBA(第3题十四大:邓小平同志建设有中国特色社会主义理论

（1)已知空气的干燥温度为60℃,湿球温度为30℃,试计算空气的湿含量H, 相对湿度叩,焓I和露点温度。 解:查表得t=30C时p=4247KkPa H,.=0622P2A(P-P2)=00272 [(t-t/rl( 30°C时r=2427a/Kn=1.09 ∴H=0.0137 t=60Cp,=19923kPa 由H=00137求得此时p=218kPa =p/ps =(1.01+188×0.0158)×60+2490×0.0158 =9644/kg千空气

6.1 C55x C/C++语言概述 6.1.1 C/C++语言概况 6.1.2 C55x C/C++语言概况 6.2 C55x C/C++语言编程基础 6.2.2 关键字 6.2.3 寄存器变量和参数 6.2.4 asm指令 6.2.5 Pragma指令 6.2.6标准ANSIC语言模式的改变(-pk,-pr和-ps选项) 6.2.7 存储器模式 6.2.8 存储器分配 6.2.9 中断处理 6.2.10 运行时间支持算法及转换程序 6.2.11 系统初始化 6.3 C55x C/C++编译器的使用 6.3.1 编译器外壳程序cl55简介 6.3.2 cl55程序的选项 6.3.3 编译器和CCS 6.4 TMS320C55x的C代码优化 6.5 C55x C和汇编语言混合编程 6.5.1 C和汇编语言混合编程概述 6.5.2 寄存器规则 6.5.3 函数结构和调用规则 6.5.4 C和汇编语言的接口