§13-5 ransmission(传输) parameters J y11+y1 2+ J I2=y21V1+y2V2h1=(y2 J 1122 2+ J V1=AV2-Bl2 A, B, C,D are T parameters l1=CV2-DI The matrix from of Tparameter equations 4 B A B Jy2=y21AD-BC=(-2)-)-(Nm-项y21y=1 For a balanced network A=D
§13-5 Transmission（传输） parameters 2 12 1 11 1 • • • I = y V + y V 2 21 2 21 22 1 1 • • • = − + I y V y y V 2 22 1 21 2 • • • I = y V + y V 2 21 11 2 21 11 22 12 1 ( ) • • • = − + I y y V y y y I y − = • • • • 2 2 1 1 I V C D A B I V A, B, C, D are T parameters. 1 2 2 • • • V = AV − B I 1 2 2 • • • I = CV − D I The matrix from of T parameter equations − = • • • • 2 2 1 1 I V T I V = C D A B T )( ) 1 1 ( )( ) ( 2 1 1 2 2 1 1 1 2 2 1 2 2 1 2 1 1 1 2 1 2 2 1 2 = 2 1 − = − − − − − = = y y y y y y y y y y y If y y AD BC For a balanced network A=D 2 • 1 I • I − + • V 2 − + • V 1
VI=Av2-Bl2 I1=CV2-DI2 TS=0 the open-circuit reverse voltage gain 0 the open-circuit transfer admittance V2I2=0 Letv2=0b Vi the short-circuit transfer impedance V2=0 the short-circuit reverse current gain 0
2 = 0 • Let I 2 2 0 1 = = • • • V I V A 2 2 0 1 = = • • • V I I C the open-circuit reverse voltage gain the open-circuit transfer admittance 2 = 0 • Let V 2 2 0 1 = = − • • • I V V B 2 0 2 1 = = − • • • V I I D the short-circuit transfer impedance the short-circuit reverse current gain 2 • 1 I • I − + • V 2 − + • V 1 1 2 2 • • • V = AV − B I 1 2 2 • • • I = CV − D I