西安石油大学：《油藏物理（油层物理学）Petro-physics》精品课程教学资源（英文课件）Physics property of reservoir rock 1.2 specific surface 岩石粒度组成与比面

1.2 specific surface Definition:specific surface means the total pores surface area of unit volume of rock. S (cm2 /cm3)

1.2 specific surface Definition: specific surface means the total pores surface area of unit volume of rock. V A S  ( / ) 2 3 cm cm

油藏物理学一一岩石粒度组成与比面 the particle size,cement content,the arrangement of particles and particle shape effect on specific surface. exp:if rock of 1 m3 is composed of sand of 1mm,the surface area is 24×104m2/m

the particle size, cement content, the arrangement of particles and particle shape effect on specific surface. exp: if rock of 1 m3 is composed of sand of 1mm，the surface area is 4 2 3 2410 m / m 油藏物理学——岩石粒度组成与比面

油藏物理学一一岩石粒度组成与比面 classification on specific surface A s is based on bulk volume S= Sp is based on Pore volume Sp- A p A SS is based on sand grain volume.Ss= s

油藏物理学——岩石粒度组成与比面 classification on specific surface : S is based on bulk volume V A S  P P V A S  S S V A S  SP is based on Pore volume SS is based on sand grain volume

油藏物理学一一岩石粒度组成与比面 relationship 1 1 Ss Sp S Induct porosity: S=Sp=(1-0)Ss

油藏物理学——岩石粒度组成与比面 relationship : S SS SP 1 1 1   P S S    S  (1)S Induct porosity:

油藏物理学一一岩石粒度组成与比面 2.Measurement of specific surface (1)directness: Kozeny-Carman equation: A·H S,=14a-V21 Ss:based on sand grain volume

2．Measurement of specific surface （1）directness： Kozeny-Carman equation： SS：based on sand grain volume Q L A H Ss          2 3 (1 ) 14 油藏物理学——岩石粒度组成与比面

油藏物理学一一储层岩石的渗透率 Pressure gage desiccator Core holder Gas Flowmeter vase design process on experimental device of specific surface

油藏物理学——储层岩石的渗透率 Core holder Gas vase desiccator Pressure gage Flowmeter design process on experimental device of specific surface

油藏物理学一一储层岩石的渗透率 (2)Indirect method a.If we knownΦ、K,how to get S K- 2x22*10

油藏物理学——储层岩石的渗透率 （2） Indirect method ： a．If we known Ф、K, how to get S 3 2 2 3 10 2   S K  

油藏物理学一一岩石粒度组成与比面 t=1 5=wpy是 b.If we known sand size distribution andΦ， how to get S s=∑g 100 Do you know how to get the equation?

b．If we known sand size distribution and Ф, how to get S τ=1 K S   7000 Do you know how to get the equation?     i i d G S C 100 6(1 ) 油藏物理学——岩石粒度组成与比面

油藏物理学一一岩石粒度组成与比面 The line on deducing relationship between sand size distribution and specific surface: 1.The particle is assumed to be n typies sphere 2.Demand the specific surface of these sphere

油藏物理学——岩石粒度组成与比面 The line on deducing relationship between sand size distribution and specific surface: 1. The particle is assumed to be n typies sphere 2. Demand the specific surface of these sphere

3.if the rock is composed of several different spheres,we can calculate the specific surface of the spheres 4.Correction for sphericity

3. if the rock is composed of several different spheres, we can calculate the specific surface of the spheres 4. Correction for sphericity