H3()=yao(x)+yai()+yP(x)+yiB(x) 其中 (x)=1aa(x1)=0ka(x)=0a(x1)=0 a1(x)=0g(x)=1a(x)=0a(x)=0 B(x)2=0B6(x)=0(x)=1B(x)=0 B1(x)2=0B1(x)2=0B(x)=0-(x)=1 可知x1是a(x)的二重零点,即可偎设 a0(x)=(x-x1)2(ax+b) 由 (x)=0其中 ( ) 1 a0 x0 = ( ) 0 b0 x0 = ( ) 1 b0 ¢ x0 = ( ) ( ) ( ) ( ) ( ) 3 0 0 1 1 0 0 1 1 H¢ x = y a¢ x + y a¢ x + y ¢b¢ x + y ¢b¢ x ( ) 0 a0 x1 = ( ) 0 a1 x0 = ( ) 1 a1 x1 = ( ) 0 b0 x1 = ( ) 0 b1 x0 = ( ) 0 b1 x1 = ( ) 0 a0 ¢ x0 = ( ) 0 a0 ¢ x1 = ( ) 0 a1 ¢ x0 = ( ) 0 a1 ¢ x1 = ( ) 0 b0 ¢ x1 = ( ) 0 b1 ¢ x0 = ( ) 1 b1 ¢ x1 = 可知 x1是a0 (x)的二重零点,即可假设 ( ) ( ) ( ) 2 0 1 a x = x - x ax + b ( ) 1 a0 x0 = ( ) 0 由 a0 ¢ x0 =