设p2x)=x2+421X+22 ∫1·g,(ec=0∫,xp,(x)k=0 ∫,(x2+ax+az)c=0∫x(x2+ax+a2)dc=0 2/3+222=0 422=-1/3 221/3=0 42=0 所以, 0,()=x2- 3 55 设 2(x) = x2 + a21x + a22 1 ( ) 0 1 1 2 x dx ( ) 0 1 1 2 x x dx 3 1 ( ) 2 所以 2 x x , ( ) 0 1 1 21 22 2 x a x a dx ( ) 0 1 1 21 22 2 x x a x a dx a22= - 1/3 a21=0 2/3+2a22 = 0 2a21 /3=0