取对数h(4)=nh-2∑x i-1 令 In l()= ∑ X三0 12 解得λ的极大似然估计值为 = x 极大似然估计量为元=n ∑X 上页取对数 − = − n i i L n x 1 ln () ln   令 ln ( ) 0 1 = − = = n i i x n L d d    解得λ的极大似然估计值为 x x n n i i 1 ˆ 1 = = =  极大似然估计量为 X X n n i i 1 ˆ 1 = = = 