2.lim 1+xcot x )cotx =1 im(1+ 2x cotx x→>0 1-x x→0 1-x 10 In(1+)~各 ·没) =e0 复习：若limu(x)=0,limv(x)=oo,则有 x→x0 x-→X0 lim v(x)u(x) lim [1+u(x)]v(x)=e x→X0 lim v(x)In[1+u(x)] x→x00 2. lim x→ ( ) x x x cot 1 1 − + 0 lim → = x x x x cot ) 1 2 (1 − + = e x x x x − − + 1 2 1 2 ln(1 ) ~ 2 = e 则有   ( ) lim 1 ( ) 0 v x x x + u x → 复习: 若 lim ( ) 0, 0 = → u x x x lim ( ) , 0 =  → v x x x = e = e lim ( ) ( ) 0 v x u x x→x lim ( ) 1 2 sin cos 0 x x x x x − →   1