正在加载图片...
解: a'=asin60°=r8 a"=ac0s60°=ro2 两式相除: 860°= d 02 2.0=3o2 d 6=V3o2 do =3dp do=3o o do.dp=√3o dt do 0=0,ev3o do dt =@e3o edo adt eh-ml+C 、 1 p=万h1-5a, 解:动点M,动系OD杆 t=1s时,中=30° D OM=108 0= 2π2 3 C Va=V。+V y=0M0=0C.9=3x2 coso y,==23m2y=y,sn0=V3x2 cos   3 0 e dt d = e d dt 0 3    = − − e = t + C − 0 3 3 3   t 1 3 0 1 ln 3 1   − = a φ O = a = r  a sin 60 τ n 2 a = acos60 = r  两式相除: 2 60   =  tg 2  = 3 2 3  = dt d 2 3     = d d dt d 2  3    = d d    d d = 3   =       0 3 0 d d    3 0 = e φ A B C O D M 解:动点M,动系OD杆 ve va vr 2 3 cos    =  =  =  ve OM  OC 2 2 3 cos   = = e a v v 2 vr = va sin  = 3 t =1s 时,φ=300 2 36 3 3 108 OM =  =  v a =v e +v r vr va ve 解:
<<向上翻页向下翻页>>
©2008-现在 cucdc.com 高等教育资讯网 版权所有