4可逆阵的QR分解 设ax1…,an线性无关,a1∈R", B1= 1 a2=(a2,a)e1+B1e2, an=(a, e)e+.+(an,n-en-1+Bonle 半 (a1…an)=(e1…en Bn5 4.可逆阵的Q R分解. , , , 1 n 设   n 线性无关，i  R , 1 1 1 1  =  =  e ( , ) , 2 2 1 1 2 2  =  e e +  e    ( , ) ( , ) . n n 1 1 n n 1 n 1 n n  =  e e + +  e e +  e  − − ( ) ( )             = n n n e e     * * * 1 1 1       