它的分布 液 ux(t)=E[X (t)]=E(Xo+tV)=EXo+tEV=0 Y(t1,t2)=E[X(t1)X(t2)]=E[(Xo+tiv)(Xo+t2V)] =E[X]+t1t2E[V]=1+tt2. 10/28 GoBack FullScreen Close Quit10/28 kJ Ik J I GoBack FullScreen Close Quit ß©Ÿ. µX(t) = E[X(t)] = E(X0 + tV ) = EX0 + tEV = 0 γ(t1, t2) = E[X(t1)X(t2)] = E[(X0 + t1V )(X0 + t2V )] = E[X2 0 ] + t1t2E[V 2 ] = 1 + t1t2