则对f(x)=anx+an1xm+…+ax+an有 b ∫/(xk=(nx+anxm1+…+ax+a) x"dx x"x+…+axhk+a ∑4x+an24x+…+a∑4x+a∑4 i=0 ∑4(anx"+an …+ax2+a fix: ∑Af(x) 66 ( ) 1 1 1 0 ( ) b b m m m m a a f x dx a x a x a x a dx −   = + + + + − 1 1 1 0 b b b b m m m m a a a a a x dx a x dx a xdx a dx − = + + + + +     − 1 1 1 1 0 0 0 0 0 n n n n m m m i i m i i i i i i i i i a A x a A x a A x a A − − = = = = = + + + +     ( ) 1 1 1 0 0 n m m i m i m i i i A a x a x a x a − − = = + + + +  0 ( ) n i i i A f x = =  。 则对 1 1 1 0 ( ) m m m m f x a x a x a x a − = + + + + − 有