江画工太猩院 例2求函数y=f"lp(inx")的导数. 解 y=nfl(sin x ")·∫p"(sinx") np"(sinx")·g(sinx")·c0sx"·nxn1 n.x"-cosx"f"-Io"(sin x") (sinx")fio"(sinx")) (sinx")江西理工大学理学院 例2 求函数 [ (sin )]的导数. n n n y = f ϕ x 解 [ (sin )] [ (sin )] n 1 n n n n y′ = nf ϕ x ⋅ f ′ ϕ x − (sin ) (sin ) n 1 n n ⋅ nϕ x ⋅ ϕ′ x − 1 cos − ⋅ ⋅ n n x nx (sin ) [ (sin )] (sin ). cos [ (sin )] 1 3 1 1 n n n n n n n n n n x f x x n x x f x ϕ ⋅ ′ ϕ ⋅ ϕ′ = ⋅ ⋅ ϕ ⋅ − − −