.1326 北京科技大学学报 第30卷 f0.20.40 0.10.60.8 o 00 0 0.10.8 R1-月0.70.40.30.60.30.2 f20.20.20.20.4 0.50.2 f30.10.10.70.20.10 Rs9=f30.20.30.2 0.40.4 0 f400.100.100」 f40.20.40.40.2 0 0 nf 00.20 00.40.8 f50.40.10.2 0 0 0 模糊评价结果为: 2=0.50.40.30.50.30.2 C=R.W=(8.1537,7.4729,7.3505,6.9075, f30.10.1 0.40.30.30 6.7682,7.5862,7.0497,6.9493,6.8291)T. f40.40.30.30.20 0 即: f 00.2 0 00.40.8 C1=8.1537,C2=7.4729,C3=7.3505, f20.50.3 0 0.50.30.2 C4=6.9075,C5=6.7682,C6=7.5862, Rs3=f30.10.10.30.30.30 C7=7.0497,C8=6.9493,C9=6.8291. f40.40.40.40.20 0 归一化为: f5L000.30 00J C=(0.1253,0.1148,0.1129,0.1062, 0.1040,0.1166,0.1083,0.1068,0.1050). f o 0 0 0 0.10.8 所以供应商排序为S1>S6>S2>S3>S7>s8> f20.20.40.20.40.50.2 S4>S9>S5. Rs4=f30.20.10.30.40.40 3.2定量指标的处理及两种评价结果的综合 f40.40.40.40.40 0 (1)按式(2)~(5)对定量指标进行处理,求得定 f5L0.20.10.10.20 0J 量指标权重为: W=(0.0373,0.0079,0.7350,0.0040, f[00 00 0.10.7 0.0292,0.07139,0.1151)T f20.20.20.20.30.30.2 (2)用T0PSIS法进行评价.按式(6)~(11)求 Rs5=f30.20.30.40.50.50 得各供应商与理想解的相对接近度分别为: f40.20.40.40.20.1 0 C1=0.5889,C2=0.0618,C3=0.5914, f0.40.10.2000」 C4=0.0294,C5=0.9159,C6=0.0597, C7=0.0111,C8=0.5269,Cg=0.9920. f0.10.2 0 0 0.60.8 归一化为: f20.40.40.3 0.60.3 0.2 C2=(0.1560,0.0163,0.1567,0.0078, Rs6- f30.10.10.4 0.30.1 0 0.2425,0.0155,0.0028,0.1397,0.2627). f40.40.30.30.10 0 供应商排序为s9>S5>S3>S1>S8>s2>s6> S4S7. f1 0 0.10 0 0.40.8 (③)定性评价与定量评价综合,由于本文中定 f20.30.30.20.5 0.30.2 性指标与定量指标的重要程度是相当的,所以取定 Rs7=f30.10.10.30.30.30 性指标与定量指标的权重比为1:1.C+C2可得: f40.40.40.40.20 0 C°=(0.2813,0.1311,0.2696,0.1140, f0.20.10.1000J 0.3466,0.1321,0.1112,0.2465,0.3676). f00.10 各供应商的综合评价值为: 00.40.8 C1=0.2813,C2=0.1311,C3=0.2696, f20.30.30.20.50.30.2 C4=0.1140,C5=0.3466,C6=0.1321, Rs8=f30.10.10.30.30.30 C7=0.1112,C8=0.2465,C9=0.3676. f40.40.40.40.20 0 则供应商最后总的排名为S9>S5>S1>S3>s8> f50.20.10.1000 S6>S2>ST>S4.R S 1 = f 1 f 2 f 3 f 4 0 ∙ 2 0 ∙ 4 0 0 ∙ 1 0 ∙ 6 0 ∙ 8 0 ∙ 7 0 ∙ 4 0 ∙ 3 0 ∙ 6 0 ∙ 3 0 ∙ 2 0 ∙ 1 0 ∙ 1 0 ∙ 7 0 ∙ 2 0 ∙ 1 0 0 0 ∙ 1 0 0 ∙ 1 0 0 R S 2 = f 1 f 2 f 3 f 4 0 0 ∙ 2 0 0 0 ∙ 4 0 ∙ 8 0 ∙ 5 0 ∙ 4 0 ∙ 3 0 ∙ 5 0 ∙ 3 0 ∙ 2 0 ∙ 1 0 ∙ 1 0 ∙ 4 0 ∙ 3 0 ∙ 3 0 0 ∙ 4 0 ∙ 3 0 ∙ 3 0 ∙ 2 0 0 R S 3 = f 1 f 2 f 3 f 4 f 5 0 0 ∙ 2 0 0 0 ∙ 4 0 ∙ 8 0 ∙ 5 0 ∙ 3 0 0 ∙ 5 0 ∙ 3 0 ∙ 2 0 ∙ 1 0 ∙ 1 0 ∙ 3 0 ∙ 3 0 ∙ 3 0 0 ∙ 4 0 ∙ 4 0 ∙ 4 0 ∙ 2 0 0 0 0 0 ∙ 3 0 0 0 R S 4 = f 1 f 2 f 3 f 4 f 5 0 0 0 0 0 ∙ 1 0 ∙ 8 0 ∙ 2 0 ∙ 4 0 ∙ 2 0 ∙ 4 0 ∙ 5 0 ∙ 2 0 ∙ 2 0 ∙ 1 0 ∙ 3 0 ∙ 4 0 ∙ 4 0 0 ∙ 4 0 ∙ 4 0 ∙ 4 0 ∙ 4 0 0 0 ∙ 2 0 ∙ 1 0 ∙ 1 0 ∙ 2 0 0 R S 5 = f 1 f 2 f 3 f 4 f 5 0 0 0 0 0 ∙ 1 0 ∙ 7 0 ∙ 2 0 ∙ 2 0 ∙ 2 0 ∙ 3 0 ∙ 3 0 ∙ 2 0 ∙ 2 0 ∙ 3 0 ∙ 4 0 ∙ 5 0 ∙ 5 0 0 ∙ 2 0 ∙ 4 0 ∙ 4 0 ∙ 2 0 ∙ 1 0 0 ∙ 4 0 ∙ 1 0 ∙ 2 0 0 0 R S 6 = f 1 f 2 f 3 f 4 0 ∙ 1 0 ∙ 2 0 0 0 ∙ 6 0 ∙ 8 0 ∙ 4 0 ∙ 4 0 ∙ 3 0 ∙ 6 0 ∙ 3 0 ∙ 2 0 ∙ 1 0 ∙ 1 0 ∙ 4 0 ∙ 3 0 ∙ 1 0 0 ∙ 4 0 ∙ 3 0 ∙ 3 0 ∙ 1 0 0 R S 7 = f 1 f 2 f 3 f 4 f 5 0 0 ∙ 1 0 0 0 ∙ 4 0 ∙ 8 0 ∙ 3 0 ∙ 3 0 ∙ 2 0 ∙ 5 0 ∙ 3 0 ∙ 2 0 ∙ 1 0 ∙ 1 0 ∙ 3 0 ∙ 3 0 ∙ 3 0 0 ∙ 4 0 ∙ 4 0 ∙ 4 0 ∙ 2 0 0 0 ∙ 2 0 ∙ 1 0 ∙ 1 0 0 0 R S 8 = f 1 f 2 f 3 f 4 f 5 0 0 ∙ 1 0 0 0 ∙ 4 0 ∙ 8 0 ∙ 3 0 ∙ 3 0 ∙ 2 0 ∙ 5 0 ∙ 3 0 ∙ 2 0 ∙ 1 0 ∙ 1 0 ∙ 3 0 ∙ 3 0 ∙ 3 0 0 ∙ 4 0 ∙ 4 0 ∙ 4 0 ∙ 2 0 0 0 ∙ 2 0 ∙ 1 0 ∙ 1 0 0 0 R S 9 = f 1 f 2 f 3 f 4 f 5 0 0 0 0 0 ∙ 1 0 ∙ 8 0 ∙ 2 0 ∙ 2 0 ∙ 2 0 ∙ 4 0 ∙ 5 0 ∙ 2 0 ∙ 2 0 ∙ 3 0 ∙ 2 0 ∙ 4 0 ∙ 4 0 0 ∙ 2 0 ∙ 4 0 ∙ 4 0 ∙ 2 0 0 0 ∙ 4 0 ∙ 1 0 ∙ 2 0 0 0 . 模糊评价结果为: C 1 = R · W = ( 8 ∙ 1 5 3 7 7 ∙ 4 7 2 9 7 ∙ 3 5 0 5 6 ∙ 9 0 7 5 6 ∙ 7 6 8 2 7 ∙ 5 8 6 2 7 ∙ 0 4 9 7 6 ∙ 9 4 9 3 6 ∙ 8 2 9 1 ) T. 即: C1=8∙1537C2=7∙4729C3=7∙3505 C4=6∙9075C5=6∙7682C6=7∙5862 C7=7∙0497C8=6∙9493C9=6∙8291. 归一化为: C1=(0∙12530∙11480∙11290∙1062 0∙10400∙11660∙10830∙10680∙1050)T. 所以供应商排序为 S1>S6>S2>S3>S7>S 8 > S 4 > S 9 > S 5. 3∙2 定量指 标 的 处 理 及 两 种 评 价 结 果 的 综 合 ( 1 ) 按 式 ( 2 ) ~ ( 5 ) 对 定 量 指 标 进 行 处 理 求 得 定 量 指 标 权 重 为 : W = ( 0 ∙ 0 3 7 3 0 ∙ 0 0 7 9 0 ∙ 7 3 5 0 0 ∙ 0 0 4 0 0 ∙ 0 2 9 2 0 ∙ 0 7 1 3 9 0 ∙ 1 1 5 1 ) T. (2) 用 TOPSIS 法进行评价.按式( 6 ) ~ ( 1 1 ) 求 得 各 供 应 商 与 理 想 解 的 相 对 接 近 度 分 别 为 : C 1 = 0 ∙ 5 8 8 9 C 2 = 0 ∙ 0 6 1 8 C 3 = 0 ∙ 5 9 1 4 C 4 = 0 ∙ 0 2 9 4 C 5 = 0 ∙ 9 1 5 9 C 6 = 0 ∙ 0 5 9 7 C 7 = 0 ∙ 0 1 1 1 C 8 = 0 ∙ 5 2 6 9 C 9 = 0 ∙ 9 9 2 0. 归一化为: C2=(0∙15600∙01630∙15670∙0078 0∙24250∙01550∙00280∙13970∙2627) T. 供应商排序为 S9>S5>S3>S1>S8>S2>S 6 > S 4 > S 7.(3) 定 性 评 价 与 定 量 评 价 综 合.由 于 本 文 中 定 性 指 标 与 定 量 指 标 的 重 要 程 度 是 相 当 的 所 以 取 定 性 指 标 与 定 量 指 标 的 权 重 比 为 1 ∶ 1.C 1 + C 2 可 得 : C 0 = ( 0 ∙ 2 8 1 3 0 ∙ 1 3 1 1 0 ∙ 2 6 9 6 0 ∙ 1 1 4 0 0 ∙ 3 4 6 6 0 ∙ 1 3 2 1 0 ∙ 1 1 1 2 0 ∙ 2 4 6 5 0 ∙ 3 6 7 6 ) T. 各供应商的综合评价值为: C1=0∙2813C2=0∙1311C3=0∙2696 C4=0∙1140C5=0∙3466C6=0∙1321 C7=0∙1112C8=0∙2465C9=0∙3676. 则供应商最后总的排名为 S9>S5>S1>S3>S 8 > S 6 > S 2 > S 7 > S 4. ·1326· 北 京 科 技 大 学 学 报 第 3 0 卷