概车纶与款理统外 所以limF(x)=limP{X≤x}=1. x→00 X→00 (4)1imF(x)=F(x),(-oo<x,<oo). x→x0 即任一分布函数处处右连续 ↑F(x) 0,x<0, 1: p1,0≤x<X F(x)= P P2,X1≤<x2, 1,x≥x2: 0 X2(4) lim ( ) ( ), ( ). 0 0 0 = −     + → F x F x x x x 即任一分布函数处处右连续.              = 1, . , , , 0 , 0, 0, ( ) 2 2 1 2 1 1 x x p x x x p x x x F x lim ( ) = lim {  } = 1. → → F x P X x x x 所以 o x F(x) • 1 x • 2 x  p1  2 p 1