联立四式解得： a= m,m-是 mmm mM, R m +2 m1+m2 mM R m1+m,+2 当不计滑轮质量和摩擦力矩时： m=0,Mr=0 m-mg T=T= 22g m2+m1 m1+m2 冈------------------------------------------------------------------------------- 联立四式解得： ( ) m m m R M m m g a f 2 1 1 2 2 1 + + − − = ( ) 2 2 2 1 2 1 2 1 1 1 m m m R m M m g m m T m g a f + +  −      + = + = ( ) 2 2 2 1 2 2 1 2 2 2 m m m R m M m g m m T m g a f + +  +      + = − = 当不计滑轮质量和摩擦力矩时: m = 0, Mf = 0 g m m m m a 2 1 2 1 + − = g m m m m T T 1 2 1 2 1 2 2 + = =