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选择题] 容易题1-36,中等题37-87,难题88-99。 x+3y+2z+1=0 1.设有直线L 及平面x:4x-2 2=0,则直线L 2x-y-10+3=0 (A)平行于丌。(B)在上丌。(C)垂直于x。(D)与丌斜交 2.二元函数∫(x,y)= (x.(09在点0处() (x,y)=(0,0) (A)连续,偏导数存在 (B)连续,偏导数不存在 (C)不连续,偏导数存在 (D)不连续,偏导数不存在 设函数n=Mx9)1=x由方程组{=2+”。确定,则当n一时, y=u +l (C)-l (D) 答:B
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5.1 Digital Processing of Continuous-Time Signals Digital processing of a continuous-time signal involves the following basic steps: (1) Conversion of the continuous-time signal into discrete-time signal, ()Processing of the discrete-time signal, (3) Conversion of the processed discrete- time signal back into a continuous-time signal
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1) provide some clues to what makes a Nobel Prize Winner. 2) give guidance to learners to listen and talk about famous person. 3) provide students with new words and expressions 4) learn how to analyze word formation 5) ask learners to write in a chronological sequence
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HEAT EXCHANGER NETWORK SYNTHESIS 1: TARGETING OBJECTIVES: 1 Determine the minimum energy inputs required for a process 2Determine the minimum number of heat exchangers required to transfer this energy 3Develop a methodology for determining where these heat exchangers should be placed in the process
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内容提要: 5-1MC-51单片机最小系统 5-2存储器的扩展 5-3并行/0端口的扩展方法 5-4可编程并行接口芯片8255A 5-5可编程并行接口芯片8155 5-6常用通道配置与接口技术 5-7DA转换 5-8A/D转换
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一、是非题(本大题6小题,每小题2分,共12分 1.图a所示结构周期为T,则图b所示体系周期为T=2+T2+3()k 2.结构刚度(也称劲度)方程,其矩阵形式为:(a)(b)}=P}它是整个结构所应满足的变形条件()
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选择题 【题3.1】在C语言中(以16位PC机为例),5种基本数据类型的存储空间长度的排列顺 序为 A) char
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1 中断概念及处理过程 2 8086的中断系统 3 可编程中断控制器8259A及其应用 4 总结
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Nash equilibrium has undoubtedly proved to be the most influential idea in game theory. enabled fundamental breakthroughs in economics and the social sciences. Its development was a major intellectual achievement; what is perhaps more important, it Recent foundational research has emphasized the subtleties in the interpretation of Nash equilibrium. This lecture deals with the technical details of equilibrium analysis, but also with these interpretational issues. However, a more precise appraisal of the situation must
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使用分析纯试剂配料,在1350℃保温1 h的条件下合成了A/S=5(Al2O3与SiO2质量比)的铝酸钙熟料.研究了钙铝比C/A(除去与SiO2结合的CaO后CaO与Al2O3的摩尔比)对熟料中12CaO·7Al2O3晶体结构及其氧化铝浸出性能的影响,并通过X射线衍射和X射线荧光等分析手段对其作用机理进行了探讨.结果表明:由于12CaO·7Al2O3量的增加,C/A=1.0~1.4时,石灰烧结法熟料溶出率随着C/A的提高而提高;在C/A=1.4时,熟料溶出率最高可达93.30%,此时CaO的缺失形成了有缺陷的12CaO·7Al2O3,且其中CaO的物质的量小于11.3 mol;钙铝比提高到1.7时熟料溶出率又出现了下降趋势,这是由于CaO的饱和导致12CaO·7Al2O3晶体择优生长取向发生变化,由(211)面开始向(420)晶面转变
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