确定局部损失系数的实验方法 例用U形压差计测量水平放置弯管的局部损 失系数。已知d=0.25m,Q=0.04m3/s,U 形管工作液体的密度P=1600kg/m3。如果 测得△h=70mm,试计算5 解忽略沿程损失,对1和2断面列出伯努利方程

Statistical approach to estimation Examine the multivariate Gaussian distribution: (x-)\v-(x-) Multivariant f(x)= Minimize (x-u)'v(x-u) gives largest probability density By minimizing the argument of the exponential in the probability density function, we maximize the likelihood of the estimates(MLE)

2.7 Some Important Crystallographic Formulas 1. Zone and zone equation All Planes parellel to common axis [uvw] constitute a (crystal) zone, the [u v w] zone. If (h k l) belongs to zone [u v w], then hukv+=0 2.ifhuk+hw=0,then[uvw] lies in(hk) 3. For cubic crystals, [h (h k)

一、例题精解 【例题17.1】如图17.1所示运算放大器电路中,已知u1=1V,u12=2V

1.已知x(t)<(2),求x1(t)=x(3t-2)e-12的傅立叶变换X() 2.已知x(n)<2X1(z),x2(n)<2X2(z),求x(n)*x2(n)的Z变换X(z) 3.已知x(t)=u(t+1)-u(t-1),x(t)的频谱为X()求x()d2

2.1般理论 2.1.1特征曲线与积分曲面 一阶拟线性方程具有形式 (2.1.2) 其中,u=u(x,y).称方向(a(x,y,z),b(x,y,z),c(x,y,z)是 方程(2.1.2)的特征方向,它在R3或R中的区域上定义了一 个向量场.我们称处处与方向(a,b,c相切的曲线是方程(2.1.2) 的特征曲线.设特征曲线的参数式为 x=x(t),y=y(t),z=z(t),t∈R或R中某区间

2.1已知R1=R2=102U=2V,当t=0时开关闭合求(0)i2(0)i(0+)u1(0) 2.2已知Us=10VR1=10QR2=5Q,开关闭合前电容电压为零,求开关闭合后i(0)

1.设u=a-b+2c,v=-a+3b-c.试用a、b、c表示2u-3v. 2.如果平面上一个四边形的对角线互相平分,试用向量证明这是平行四边形

习题一: 一:选择题 1、如果体系经过一系列变化,最后又变回初始状态,则体系的 A.Q=0,W=0,△=0,△=0 B.Q0,w0,△u=0,△H=Q C.Q=,△U=Q+W,△H=0 D.Q+W,AU=Q+W,AH=;

National Motto of the United States In God We Trust The phrase derives from the line \And this be our motto. 'In God is our trust, \in the battle song that later became the U.S. national anthem, \The Star-Spangled Banner. \The phrase first appeared on U. S. coins in 1864 and became