THE CELL WALL Before traversing the plasma membrane(p. m., ions must first cross the cell wall and contact the p. m the bulk flow of soil solution coul theoretically carry inorganic ions into the cell wall and through the apoplastic pathway. The thickness of a cell wall is in the range of 500 to 1000 nm. It is porous

第七章刚体的简单运动 7.1已知OA=0.1m,R=0.1m,角速度w=4rad/s; 求导杆BC的运动规律以及 y 当=30°时BC杆的速度v和加速 度a。 解BC杆直线平动,用点O1

第二章多元函数 2-3习题讨论 23-1讨论题 23-2参考解答 习题讨论 题目 )设xn,yn∈R\,且 limx=x, lim y=y,证明 lim(,,,)=(,y) (2)函数f(x,y)=(,列在R\×R\中连续 (二)在长方体T内任取一点M0,是否一定存在一张过点M的平 面∏I,将该长方体恰分成两等份 (三)设集合A,BCR”,证明

一、解释：（20%） 1、单位转速 H nD n 1 11 = 表示当 D1=1m,H=1m 时水轮机具有的转速。 2、飞逸转速 当水轮机发电机组突然丢弃全部负荷时，如调速机构失灵或其它原因使导水机构 不能关闭，机组转速将迅速升高并达到某一最大值，该转速称作飞逸转速

2.2 Estimating Overall Forces -Vertical dead loads(5～10kN/m²) -Vertical live loads = equivalent dead loads(2～5kN/m²) - Horizontal wind load - Horizontal earthquake load 2.3 Aspect Ratios and Overturn Resistance Aspect ratio (h/d) is one of the main considerations in schematic level. It is very important for overall stability of a building against overturning. 2.4 Strength and Stiffness of Buildings Carrying capacity –enough strength (against loads) Rigidity of building – enough stiffness (against deformation) 2.5 Symmetry and Asymmetry in Building Forms Asymmetry building is caused by: - asymmetry of building elevation - asymmetry of supporting system - asymmetry of dead loads or live loads

Our task How to estimate and test discount factor model. Ep,=E(m (data 1, parameter)) 1. Bring an asset pricing model to data to estimate free parameters. For example, parameter,yinm=B(c+1/c)-y Or the b in m=b f 2. Evaluate the model, is it a good model or not? Is another model better?

一、两向量的数量积 实例一物体在常力F作用下沿直线从点M1移动 到点M2,以表示位移,则力F所作的功为 W= cos0(其中为F与的夹角) 启示两向量作这样的运算,结果是一个数量 定义向量a与b的数量积为ab

介绍激光扫描粗糙度测量仪的测量原理、结构及结果。本测量仪根据激光在工件表面的反射散射原理,应用激光扫描技术、数据采集、A/D转换和定标曲线的计算机拟合,整个测量过程在单板机控制下自动完成。测量粗糙度Ra的分辨率为0.001μm,测量重复精度为0.006μm

一、两向量的数量积 实例一物体在常力F作用下沿直线从点M移动 到点M,,以5表示位移,则力F所作的功为 || coS0其中0为F与的夹角) 启示两向量作这样的运算,结果是一个数量. 定义向量a与b的数量积为b b= cos0(其中为与b的夹角)

3.1 X(eo)=2xnJe-jon where x[n] is a real sequence. Therefore X(e)=Rl∑xnlo/。 ∑xR(-mu)=∑ x[n]cos(on),and xmm)=m∑刈nm∑刈mc-m)=-2 xn] sin(oon) Since cos(on)and sin(on)are, respectively, even and odd functions of o, Xre(eJo) is an even function of o