Spring 2003 1661AC22 Longitudinal Dynamics For notational simplicity, let X=Fn, Y= Fu, and Z= F aF Longitudinal equations(1-15 )can be rewritten as mi=X+X2- mg cos(0+△X

ATTITUDE MOTION -TORQVE FeEE MANE 0ISCUSSED THE ROTATIONAL MOTION FRDn 1 ERSPECTvE。FE”6o0 FRAME 一NE0T0F1A0 A WAy TO CONNECT THE MOTION To THE INEATIAL FRAME So WE CAN DESCRI BE THE ACTUAL MOTION TYPICALLY DoNE 6y DESC RI BING MOTION oF NEHICLE ABoVT THE

Spring 2003 Generalized forces revisited Derived Lagrange s equation from d'Alembert's equation ∑m(8x+16y+22)=∑(Fx+F+F。=) Define virtual displacements sx Substitute in and noting the independence of the 8q,, for each

Spring 2003 Example Given: Catapult rotating at a constant rate(frictionless, in the horizontal plane) Find the eom of the particle as it leaves the tube

Introduction We started with one frame (B) rotating and accelerating with respect to another(), and obtained the following expression for the absolute acceleration

CoRIoLIS ACcELERAT0 EMYSTIF∈p CONSIOER CASE oF CONSTANT ROTA ToN.No AT0 N OF MME⊙AGUA,ANDc°srAT RADIAL VELOCITY ( As sEEN IN THE RomTIwG

NEWTONs L丹WS ① BoDY CoNTINUES玉 N TTS STATE OF MOT(0N DR REST UNLESS FORCED DI RECTIoNs IMPoRTA. 儿L M5T3 E AN NIERT升L ACELERATION

1轴向拉伸与压缩的概念和实例 2轴向拉伸或压缩时横截面上的内力和应力 3直杆轴向拉伸或压缩时斜截面上的应力 4材料在拉伸时的力学性能 5材料在压缩时的力学性能

1纯弯曲 2纯弯曲时的正应力 3横力弯曲时的正应力 4弯曲切应力 5*关于弯曲理论的基本假设 6提高弯曲强度的措施

1交变应力与疲劳失效 2交变应力的循环特征,应力幅和平均应力 3持久极限 4影响持久极限的因素 5对称循环下构件的疲劳强度计算 6持久极限曲线