首先，复习e=Bδlv公式，说明 e正比于Bδ。结合图2.1解释v=2πRn/60（m/s， n(r/min)）; 机械角速度Ω=v/R=2πn/60 ( r/s); 电角速度ω=pΩ=p2πn/60 (rad/s) （记下来）；导体或线圈

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轨道:与氢原子类似,其电子运动状态可描述为1s,2s,2px2p2p3s。 能量:与氢原子不同,能量不仅与n有关也与有关;在外加场的作用下,还与m有关

pleased to inform you that the goods (four containers of microwave and washing machine) under S/C No. CX-ETNSQ06 will dispatch by S.s. PRINCESS V.336on May 20th 2000 and it will arrive in TORONTO on

一、(10分)已知系统的传递函数=2且初始条件为c()=1,()=0R(s)s2+3s+2试求阶跃输入r(t)=1(1)作用时,系统的输出响应()

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一、选择题(共3题15分) 1.5分(4181) 4181在298K时,下述电池电动势为0.456V, Ag+Agl(s)KI(0.02 mol. kg, y+=0.905)KOH0.05 mol. kg+=0.820)Ag2O(s)Ag(s)当电池反应进行至电子传输量为1mol时,这时电池反应的平衡常数为:() (A)5.16×107 (B)1.9×10-8 (C)1.17×10 (D)1.22×10