#include void maino int n=I printi(40以内能同时被3和4整除的数有:m”)

#include void maino inta[2[3}={1,3,52,46} printf\数组a的第0行各元素值是:\)

#include maino int x=5, y=0, Z=6, result printf(\&&y&&z=%d\\n\,result result=x-3y‖z*5; printf(\x-3 yz*=%d\\n\, result)

#include void maino nta3[4}={1,2,34},{5,6,7,8},{19,10,11,12}} int b4 3), i,j printf“转置前的数组为:Ⅶn\)

Alkane Formulas All C-C single bonds Saturated with hydrogens Ratio:H n2n+2 Alkane homologs:ch3(ch2)nCH3 Same ratio for branched alkanes

#include void hanoi ta(intn, char tal. char ta2, char ta3);,/*函数原型* void maino printf(\请输入盘片数:\) scanf(\%d\, &n)

#include void maino int x=4, y=2, Z; y+=x+3°4%5 /*将x向左移y位后的值赋给x*/

#include void maino a[4][3],iJ, float ave, b( 4]: printf(“请输入一个4行3列的整数矩阵:m”)

#include #define n1 2 #define n2 3 void maino int a[NIJ[N2], b[N2JINI]i

#include void maino int a3]3],sum= printf\请输入一个三行三列的整数矩阵;n\)