硝基化合物是指分子中含有硝基(-NO2的化合物,可以看作是烃分子中的氢原子被硝基取代后得到的化合物,常用RNO2或ArNO2表示。 1.分类 (1)根据烃基不同可分为:脂肪族硝基化合物rnO2和芳香族硝基化合物arNO2 (2)根据硝基的数目可分为:一硝基化合物和多硝基化合物

1.1000k,101.325kpa时反应2SO3(g)=2O2(g)+o2(g)的Kc=3.54molm-3 (1)求此反应的Kp和Kx (2)求反应SO3(g)=SO2(g)+1/2O2(g)的Kp和Kx 2.已知457K,总压为101.325kPa时,NO2有5%按下式分解求此反应的

问题的提出 1、计量经济学模型,需要经常考虑属性因素的影响。例如,职业、战争与和平、繁荣与萧条、文化程度、灾害、季节 2、属性因素往往很难直接度量它们的大小。只能给出它们的“Yes—D=1”或”No一D=0”、或者它们的程度或等级

The Normal Distribution: the distribution of a continuous r.v. whose value depends on a number of factors, yet no single factor dominates the other. 1. Properties of the normal distribution: 1)The normal distribution curve is symmetrical around its mean valueu. 2)The PDF of the distribution is the highest at its mean value but tails off at its extremities

A point at which two or more elements have common connection is called node(节点). Suppose that we start at one node in a network and move through a simple element to the node at the other..., if no node was encountered more than once, then the set of nodes and elements that we have passed hrough is defined as path(路径)

[1] Abramowitz, M., and Stegun, I., Handbook of Mathematical Functions, Dover Pub￾lications, New York, 1965. [2] Adair, R., Concepts in Physics, Academic Press, New York, 1969. [3] Anderson, J., and Ryon, J., Electromagnetic Radiation in Accelerated Systems, Physical Review, vol. 181, no. 5, pp. 1765–1775, May 1969

1. 酸性 (pH≤1) - + 2+ MnO +8H +5e = Mn + 4H O 4 2  1.51  = 测定：H2O2, 2+ 2+ - H C O ,Fe ,Sn ,NO ,As(III) 2 2 4 2

he correct bibliographic citation for this manual is as follows: Delwiche, Lora D. and Slaughter, Susan J., 2003. The Little SAS
Book: A Primer, Third Edition. Cary, NC: SAS Institute Inc. The Little SAS
Book: A Primer, Third Edition Copyright © 2003, SAS Institute Inc., Cary, NC, USA ISBN 1-59047-333-7 All rights reserved. Produced in the United States of America. No part of this publication may be reproduced

1. 酸性 (pH≤1) - + 2+ MnO +8H +5e = Mn + 4H O 4 2  1.51 =测定：H2O2,2+ 2+ -H C O ,Fe ,Sn ,NO ,As(III) 2 2 4 2 2. 极强酸性，在P2O7

1.根据no =gH0 /2p,可以说明一些什么问题？ 解：这是发生核磁共振的条件．由该式可以说明：（１）对于不同的原子核，由于 磁旋比g不同，发生共振的条件不同；即发生共振时n0 和H0的相对值不同．