外研版（三起）（2012）小学英语五年级下册Module 5 Unit 1 It's big and light.Module 5 Unit 1 It's big and light.教案(6)

12.1s元素概述 12.2s区元素的单质 12.3s区元素的化合物 12.4锂、铍的特殊性对角线规则

一、判断题:试判断对错,并写出原因或相应的公式(3分×5=15分) 1.熵增原理的表达式为:△S≥0(×) 熵增原理的表达式应该为:△S隔离系统≥0 或者写为:△S系统+△S环墙≥0,(其中等号在可逆条件下成立)

1.Integrability Demand function x(p,w)(.d.) is HDO, satisfied Walras Law and have a substitution matrix S(p,w) is s.n.s.d. for any (p,w), if it's deduced by rational preference. And if we observed an x(p,w) satisfied such conditions, can we find a preference to rationalization(p,w)? That the integrability problem

1-1质点在xOy平面内的运动方程为x=3,y=27+3。求:(1)=2s时质点的位矢、速度和加速度:(2)从r=ls 到2s这段时间内,质点位移的大小和方向:(3)0~1s和1~2s两时间段,质点的平均速度;(4)写 出轨道方程

1. Integrability Demand function x(p, w)(c d ) is HDO, satisfied walras law and have a substitution matriX S(p, w) is s n.s.d. for any (p, w), if it's deduced by rational preference And if we observed an x(p, w)satisfied such conditions, can we find a preference to rationalization x(p w ) That the integrability problem

先寻找斜裂和水平裂,分开肺叶,再以各叶内的管道 确定肺段。肺静脉段间支是段间裂的标志。 1、右肺上叶尖段静脉(V1)的下支分S1和S3。后段静 脉(V2)分V1和V2及V2和V3。 2、右肺中叶V4的段间支分开S4和S5。 3、左、右肺下叶V6有上支、内侧支和外侧支,内、外 侧支为段间支,可区分上段和各底段。各底段上位层 面,以各底段静脉的高位属支(段间支)区分;在下 位层面,以“无血管区”作为分段标志

外研版（三起）（2012）小学英语五年级下册Module 5 Unit 1 It's big and light.Module 5 Unit 1 It's big and light.教案(5)

外研版（三起）（2012）小学英语五年级下册Module 5 Unit 1 It's big and light.Module 5 Unit 1 It's big and light.教案(3)

S1 蛋白质和多肽类药物概述 S2 蛋白质工程制药概述 S3 蛋白质工程的基本技术 S4 蛋白质工程制药实例