留数定理设区域G的边界C为一分段光滑的简单闭合曲线.若除有限个孤立奇点bkk= 1,2,3,…,n外,函数f(2)在G内单值解析,在中连续,且在C上没有f(z)的奇点,则

Commercial drivers Globalization trends Longer distances between producers and consumers Emerging markets, e.g. China, South America, Africa Lean manufacturing Focus on to eliminate waste, e.g. JIT Faster response to market demands

1. The good and bad sides of using triacylglycerols as an energy storage Highly reduced, more than twice as much energy as carbohydrates or proteins (~38 kJ/g vs ~18 kJ/g). Highly hydrophobic: does not raise osmolarity of cytosol, nor add extra weight; but must be emulsified before digestion and transported by special proteins in blood

一.计算模型 1.计算简图 单位厚度的受力体一个边界为平面,而在平面以下为无限大的物体。略去体力分量,取单位厚度 上所受力为P,应用逆解法求{o}。 2.边界条件 二.拉梅麦克斯方尔直角坐标方程 1.主应力迹线坐标系 主应力G和σ2正交,两个主力的迹线可以构成正交坐标系G转到σ,逆针向为正而且o增加逆针向转时为S正向

1. Carbohydrates are aldehyde or ketone compounds with multiple hydroxyl groups or substances that can yield such compounds on hydrolysis(p. 293) 1.1 Carbohydrates are the most abundant biomolecules on earth and have multiple roles in all forms of life. 1.1.1 Carbohydrates serve as energy stores (e.g., starch in plants, glycogen in animals), fuels (e.g., glucose), and metabolic intermediates (e.., ATP, many coenzymes)

Foundations of state Estimation Topics: Bayes Filters Kalman filters Hidden markov models Additional readins G. Welch and G. Bishop. An Introduction to the Kalman Filter \. University of North Carolina at Chapel Hill

Chapter 13 Cell apoptosis 1. Extracellular cotrol of cell division cell growth, and apoptosis Mitogens stimulate G1-Cdk and G1/S-Cdk activities

1.已知Ag的溶度积为8.3×10-,求(1)纯水中和(2)在0.010mol·溶液中AgI的溶 解度(g) 2.已知CaF2的溶度积为2.7×10,求(1)在纯水中;(2)在0.10mol·lnaf溶液中;(3)在 0.20mol·2溶液中CaF2的溶解度(g·)

1.氧气钢瓶内的容积为40.0L,压力为1.01Mpa,室温27℃。求钢瓶中尚有氧气的质量为多少克。 2.在容积为50L的容器中,含有140g的CO和0g的H2,温度为300K试计算: (1)CO与H2的分压;(2)混合气的总压

淡水需求:生活用水、动力装置用水、锅炉补水 海水[Sea Waters.w.)]:平均含盐量35g/ 淡水[Fresh Water.w.:含盐量<1000mg/ 造水机[Fresh Water Generator(f..g)]:所产淡水含 盐量应低于10mg/(根据锅炉补给水的要求)