Chapter F6 Power Notes Accounting Systems, Internal Controls, and Cash Learning Objectives Basic Accounting Systems 1234567 Internal Control Controls Over Cash Internal Control of Cash Receipts Internal Control of Cash Payments Bank Accounts: A Cash Control Bank Reconciliation

Chapter F5 Power notes Accounting for Merchandising Businesses Learning Objectives 1. Nature of Merchandising Business 2a. Accounting for Purchases 2b. Accounting for Sales 2c. Transportation Costs 2d. Merchandise Transactions 3. Merchandising Chart of Accounts 4. Merchandising Income Statement 5. Merchandising Accounting Cycle 6. Financial Analysis and Interpretation

Review Conditional pdf Let(Y1,., YN) have joint pdf f(31,.. JN). Let f(3J+1, .. yN)be the marginal pdf of(y+1,……,YN). The conditional pdf of y1,…, Y, given y+1,…, YN is defined by

Chapter 5 Large sample properties of the LSE 5.1 Stochastic convergence Suppose that Xn} is a sequence of random varia bles with a corresponding sequence of distribution functions{Fn} If Fn(x)(x) at every continuity point x of F, Fn is said to converge weakly to F, written FnF. In this case,{xn} is said to converge in distribution to where

最大传动比是汽车为I档时传动系的总传 动比,因主减速器传动比是固定的,通 常汽车没有分动器和轮边减速器,因此, 只要确定I档传动比即可。 最大爬坡度、I档动力因数、附着力和汽 车最小稳定车速是最大传动比的制约因 素。 讨论最大爬坡度时,车速很低,近似等 速,所以,F和F均可忽略

Chapter F3 Power notes The Matching Concept and the Adjusting Process Learning Objectives 1. The Matching Concept 2. Nature of the Adjusting Process 3. Recording Adjusting Entries 4. Summary of Adjustment Process 5. Financial Analysis and Interpretation

P1023(1,0) 4a=6.b=9 x≥0 x≥0 6(1)f(x) (2)f(x) 在x=0不可导

例1研究函数F(y)=(2dx的连续性,其中(x)是[01]上连续且为正的函 0x+y 数。 yf(x) 解令g(x,y)=2 x2+y ,则g(x,y)在[0,×[c,d]连续,其中0∈[c,d]。从而F(y)在 y≠0连续

例1设x2=n,y2=,z2=m及∫(x,y,z)=F(u,V,w),证明 xf +yf +=f=uF +vF+wF -v x=x(u, v, w) 证方程组{y2=确定了函数组{y=y(un,,w),先求这个函数组对各变元的偏导

例1设x2=n,y2=,z2=m及∫(x,y,z)=F(u,V,w),证明 xf +yf +=f=uF +vF+wF -v x=x(u, v, w) 证方程组{y2=确定了函数组{y=y(un,,w),先求这个函数组对各变元的偏导