Difficult Person Hostile-aggressie Bullies, cverwhelms, and intimidates cthers nd up to the hostile ade frot atoers-can t accept feedback on t rush into the worst thing that coul happen?)

A1, A,----two arbitrary constants S S2----real numbers or conjugate complex Since the s,t and s,t must be dimensionless, S,, S2----(1/s)

一、分析模型 前面4.1节中的分析都是在没有噪声条件下进行的本节将要研究的问题是 信道存在加性高斯白噪声时,各种线性调制系统的抗噪声性能。 分析解调器的抗噪声性能的模型如图4-1所示。图中,Sm()为已调信号, n(t)为传输过程中叠加的高斯白噪声。带通滤波器的作用是滤除已调信号频带 以外的噪声,因此,经过带通滤波器后到达解调器输入端的信号仍可认为是 m(),噪声为n(t)

一、由电路求响应 由S域等效电路 1.元件→域运算阻抗R,L,M,C→R,L,M、 sC信号→象函数i(t),u(t)→I(s),U(s)

(1)1/0方程:D(p)r(t)=N(p)e(t) (2)系统函数H(s)=(s) (3)框图/流图 (4)状态方程

加工精度 一、评定零件质量的一项重要指标。 二、表示加工的准确程度。 包括尺寸精度(国家标准ITO1、IT、IT1、1T218来表示,共20级。T01的公差值最小,精度最高。)、形状精度(国家标准规定了六项形状公差:直线度、面度、度、圆柱度/、线廓、面轮廓。)、位置精度(国家标准规定了八项位置公差⊥平行度垂直度倾斜度、同轴度对称度、位置度跳动、全跳动。)

例1一飞轮半径为0.2m、转速为150rmin-1,因 受制动而均匀减速,经30s停止转动.试求:(1) 角加速度和在此时间内飞轮所转的圈数;(2)制动开 始后t=6s时飞轮的角速度;(3)t=6s时飞轮边缘 上一点的线速度、切向加速度和法向加速度

萃取、冲洗和干燥:还没到结束不能算结束。藉由分液漏斗示 。 范液相-液相萃取并学习如何用”反应检查步骤”检查你的反应。这 是一个你不会想错失的一个纯化技巧! Extracting, Washing and Drying: It ain't over 'til it's over. Learn how to \work up\ your reaction using a separatory funnel to perform a liquid-liquid extraction. This is one purification technique you don't want to miss!

Solution General solution x(t)= A cos wnt +B sin wnt or, x(t)=Csin(wnt+φ) Initial conditions

In this lecture, we consider the problem of a body in which the mass of the body changes during the motion, that is, m is a function of t, i.e. m(t). Although there are many cases for which this particular model is applicable, one of obvious importance to us are rockets. We shall see that a significant fraction of the mass of a rocket is the fuel, which is expelled during flight at a high velocity and thus, provides the propulsive force for the rocket