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3-2正戊烷(T=36.1℃)和正己烷(Tb=6.7℃)的溶液可以认为是理想溶液,已 知两个纯组分的饱和蒸汽压(汞压差计示数,mm)和温度(℃)的关系如下 1065 正戊烷gp=6.852-1+232.0 1172 正己烷1gp2=6.878 t+224.4 试计算该二组分溶液的气-液平衡关系(用y-x函数关系表示) 36.1+68.7 解:tb=
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I Let L= 1.25 H in Fig. 6-11, and determine v(t)if v(0) 1(02)=20A L 0.05F ig 6-11 For prob. I 2(a)What value of L in the circuit of Fig 6-11 will result in a transient response of the form, v(t)
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一、空题 1.状态方程P(V-b)=RT的偏离焓和偏离熵分别是 H-H* =y-r() _R] dp=+bp=bp和 s-s +RIn= =0: ( )-H(.R) 和S(T2,P2)-S(T,P)还需要什么性质?C;其计算式分别是H(2,2)-h(,P)
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外研版(三起)(2012)小学英语六年级下册Module 7 Unit 2 She couldn't see or hear.Module 7 Unit 2 She couldn't see or hear.课件(6)
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Proof Existence and uniqueness of r(t, u)and A(t)follow from Theorem 3. 1. Hence, in order to prove differentiability and the formula for the derivative, it is sufficient to show that there exist a function C: R++R+ such that C(r)/r-0 as r-0 and E>0 such
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A1, A,----two arbitrary constants S S2----real numbers or conjugate complex Since the s,t and s,t must be dimensionless, S,, S2----(1/s)
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where f:R\×Rn×R→ R\ and g:R\×R\×R→ R are continuous functions. Assume that f, g are continuously differentiable with respect to their first two arguments in a neigborhood of the trajectory co(t), yo(t), and that the derivative
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3.1.2 A general uniqueness theorem The key issue for uniqueness of solutions turns out to be the maximal slope of a=a(a) to guarantee uniqueness on time interval T=[to, t,, it is sufficient to require existence of a constant M such that
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外研版(三起)(2012)小学英语六年级下册Module 7 Unit 2 She couldn't see or hear.Module 7 Unit 2 She couldn't see or hear.课件(3)
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EROSPACE DYNAMiCS EXAMPLE: GWE ACCELERATIoN of THE TIP 0F认ERU0毛R人TM5Hc人AF LDk小 G For A650LUT # CCELER升T10 N UTH RES/∈ct T0wE工NERT1 AL FRAME (∈ TH IN THiS CASE) 0EFNE兵8uNcH0 f PoINTS
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