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例3设n阶方阵A的伴随矩阵为A*,证明: (1)若A=0,则A=0 (2)a=ain-1 证明:由伴随矩阵的定义显然有 AA*=AA=AIEn, 两边取行列式即得 JAllAdet()=a, 故当A不等于0时,(2)是显然的。而 只要我们证明了(1),则(2)对于A|=0 的矩阵A也是成立的。下面我们证明(1)

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1.已知下列函数在指定区间上可积,用定义求下列积分: (1)|xtx(00)

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复化求积法的基本思想: 将积分区间[a,bn等分,可得到n+1个求积 节点:Xk=a+kh,(k=0,1,n),其中h=b-a