第一周作业参考答案 3.11011.011(B)=27.375(D)=33.3(O)=1B.6(H) 4.240.75(D)=110000.11(B)=360.6(O)=0.C(H) 5 E3(H)=11100011() E3(H)为原码时,x=-110011(B)=-99(D) E3(H)为反码时,[]原=10011100(B)(x=-11100=-28(D) E3(H)为补码时,[]原=10011101(B),(x=-11101=-29(D) E3(H)为无符号数时,X=E3(H)=227(D) 因为E3(H)的高4位E(H)=14(D)超出了0~9的范围,所以E3(H)不可能为压缩BCD码

以CSP流程生产的含B和无B的SPHD冷轧基板为实验材料,运用拉伸实验、金相观察、SEM、TEM和EBSD手段,对比分析了两种钢的力学性能、组织、析出物、位错密度和晶体学取向的变化.研究表明:微合金元素B的加入明显使SPHD冷轧基板的铁素体晶粒粗大化,钢中有粗大的析出相粒子产生,且位错密度下降,从而引起屈服强度的降低.采用背电子散射EBSD技术分析了无B和含B钢的晶体学取向,其取向主要为大角度晶界,且无B钢中存在着大量的亚晶

研究了添加Dy和Nb对纳米复合Pr2Fe14B/α-Fe永磁合金形成,组织结构及磁性的影响。结果表明:Pr9Fe85B6非晶带的晶化过程,在α-Fe相初始晶化之后,出现Pr2Fe23B3亚稳相,最终形成Pr2Fe14B+α-Fe两相组织.而添加Dy或同时添加Dy和Nb后晶化过程不出现亚稳相.添加Dy和Nb元素显著地提高了纳米复合永磁合金的磁性能。最终获得了磁性能为HCI=702.4kA/m,Br=1.03T,(BH)max=132.6kJ/m3的纳米晶复合Pr8Dy1Fe84Nb1B6永磁材料

概率论与数理统计模拟试题(1) 填空题 1.已知事件AB满足P(AB)=P(AB),且P(A)=P,则B)=() 2.设P(A=04,P(A∪B)=0.7,则(1)若A、B互不相容时,P(B)=() (2)若A、B相互独立时,P(B)=() 3.在1中随机取两个数,则事件“两数之和小于65的概率为()

第十二章祖国完全统一的构想习题答案 一、单项选择题 1B 2B 3C 4 B 5A 6C 7D 9B 10C 11C 12D 13A 14B 15C 16D 17D 18B

铁磁质 一、铁磁质及其磁化 铁磁质B>B铁、镍、钴、铁氧体 对于顺磁质与抗磁质,B与H有线性关系, 磁导率μ为一常量。即: B= 对于铁磁质,B与H之间的关系比较复杂, 磁导率μ不是一个常量。 由实验所测定的B与H之间的关系曲线 称为磁化特性曲线

定理假设函数x)在区间[a,b]上连续,函数x=()满 足条件:(1)o(a)=a,以B)=b;(2)∞(1)在[a,(或B,a)上具 有连续导数,且其值域不越出[a,b],则有

一正交矩阵的定义与性质 1.定义 若n阶方阵A满足A'A=E,则称A为正交矩阵 2.性质 (1)=±1;(:'=e,A'A=1,a=1) (2)A,B为正交矩阵,则AB也是正交矩阵; (:(AB)(AB)=B'(A'A) B=B'B=E.) (3)A是正交矩阵A-1=A;AA=E) (4)A是正交矩阵A也是正交矩阵;

High temperature corrosion tests in 75%Na2SO4-25%. NaCl molten salt have been conducted on waspalloy specimens plasma sprayed with Co-Cr-B-Si, Ni-Cr-B-Si-hCr3C2, X-40, X-40 + TiC and Ni/Al + Al2O3 coatings, test coupons were exposed isothermally at 750℃up to 200 h. After the corrosion tests, each sample was examined by OM, SEM and EMPA. It was found that X-40, X-40 + TiC and Ni/Al + Al2O3 were violently corroded by the molten salt due to cracking and spalling of the coatings, whereas Co-Cr-B-Si and Ni-Cr-B-Si + Cr3C2 exhibited superior corrosion resistance, which were thought to be related to the formation of chromium and silicon oxide film. A possible corrosion mechanism had been proposed and it is suggested that the excellent corrosion resistance and high hot-hardness of the two B-Si containing coatings may be of significance for applications in petroleum refining industry as

(1) Hole particle current from E to B (2)Electron particle current from B to E (3)Recombination current in B (4) Hole particle current originating in E and reaching C (5)Reverse electron particle current from c to B (6) Reverse hole particle current from b to c (What is difference between \current\ and\particle current ? OE F Schubert, Rensselaer Polytechnic Institute, 2003