The state of stress at a point is completely determined when: 1. the stress vectors on three different planes are specified 2. the stress vectors on two different planes are speciale 3. the stress vectors one arbitrary plane is spec-

一、综述 二、传统观点认为库存管理是对物料进、出、存的业务管理,这种理解是不全面的。 三、APICS对库存的定义是“以支持生产、维护、操作和客户服务为目的而存储的各种物料,包括原材料和在制品、维修件和生产消耗、成品和备件

Why is the element stiffness matrix singular in a finite element formulation? 1. So that it can accomodate rigid element dis- placements without introducing spurious nodal 2 Because we made a mistake in the formula- tion the stiffness matrix should not be sin- g 3. Because we havent enforced any displace ment boundary conditions(it's a variational approach after all) Statement(1)

第一节抽样调查的意义特点 第二节抽样调查的历史发其实践 第三节抽样调查的分类与设计 第四节抽样调查的基础理论

1.掌握材料在轴向拉压时的力学性能。 2.掌握材料在常温静载作用下三种强度失效准则及其应用:最大切应力准则,奇变能密度准则,最大拉应力准则

We are going to consider the forces exerted on a material. These can be external or internal. External forces come in two flavors: body forces(given per unit mass or volume) and surface forces(given per unit area). If we cut a body of material in equilibrium under a set of external forces along a plane as shown in fig. 1. and consider one side of it we draw two conclusions: 1 the equilibrium provided by the loads from the side taken out is provided by a set of forces that are distributed among the material particles adjacent to

一、确定系统中的对象 二、确定对象的属性及操作 三、测试对象的有效性 四、区分对象和类 五、说出面向对象的编程和过程化编程之间的区别 六、解释封装的主要好处 七、列出软件开发的主要步骤

For the potato-shaped body given in class to explain the concept of stress, the field of stress vectors t(n)=t(n)(x)on the plane of normal n given by its cartesian components(1,0, 0) known and its cartesian components are given by the expression

The reaction on the left end is not exact because 1. The order of interpolation is too low, a higher order of interpolation would give the right reaction 2. The distributed load attributed to node one does not ke it into the solution

The finite element method In FEMi we derale finite element equations fro PVD swe- SWe and obtained: K0=R:=4…n waere n:number of element nodal p Ue: elenent nodal displace ents