一、基本概念 1.函数极限的定义: (1)x→+∞时函数极限的定义:设f为定义在[+∞)上的函数,A为实数。若对任 给的>0,存在正数M(≥a),使得当x>M时有f(x)-Ak,则称函数f当x→+∞ 时以A为极限

一、选择题(共3题15分) 1.5分(4181) 4181在298K时,下述电池电动势为0.456V, Ag+Agl(s)KI(0.02 mol. kg, y+=0.905)KOH0.05 mol. kg+=0.820)Ag2O(s)Ag(s)当电池反应进行至电子传输量为1mol时,这时电池反应的平衡常数为:() (A)5.16×107 (B)1.9×10-8 (C)1.17×10 (D)1.22×10

一、例题精解 【例题20.1】单相桥式可控整流电路如图20.1所示,已知R=20Q,要求U在0-60V的范围内连续可调。(1)估算变压器副边电压值U2(考虑电源电压的10%波动);

一、例题精选 【例题22.1】当基本RS触发器的R和S端加上图22.1所示的波形时试画出Q端的输出波形。设初始状态为“0”和“1”两种情况

一、例题精选 【例题5.1】有一电容元件,C=0.5F,今通入一三角波形的周期电流(图5.1(b),(1)求电容元件两端电压uc;(2)作出u波形;(3)计算t=2.5s时电容元件的电场中储存的能量。设uco=0

Handout 7: Lag and PI compensation Eric Feron Lag Compensation goals: Raise gain at low frequencies while leaving rossover &z higher frequencies untouched b≥0. When b=0: Add an integrator in the loop Typical lag Bode Plot

测1.1现有两种说法:①塑性材料中若某点的最大拉应力mx=s,则该点一定会产生屈 服;②脆性材料中若某点的最大拉应力max=0b,则该点一定会产生断裂,根据第

1.氧气钢瓶内的容积为40.0L,压力为1.01Mpa,室温27℃。求钢瓶中尚有氧气的质量为多少克。 2.在容积为50L的容器中,含有140g的CO和0g的H2,温度为300K试计算: (1)CO与H2的分压;(2)混合气的总压

1 Induction Recall the principle of induction: Principle of Induction. Let P(n) be a predicate. If ·P(0) is true,an for all nE N, P(n) implies P(n+1), then P(n) is true for all nE N As an example let's try to find a simple expression equal to the following sum and then use induction to prove our guess correct 1·2+2·3+3:4+…+n·(mn+1) To help find an equivalent expression, we could try evaluating the sum for some small n and(with the help of a computer) some larger n sum

1 The Number-Picking Game Here is a game that you and I could play that reveals a strange property of expectation. 3, First, you think of a probability density function on the natural numbers. Your distri- bution can be absolutely anything you like. For example, you might choose a uniform distribution on 1, 2, ... 6, like the outcome of a fair die roll. Or you might choose a bi- probability, provided that,...,n. You can even give every natural number a non-zero nomial distribution on 0, 1 he sum of all probabilities is 1