点击切换搜索课件文库搜索结果(983)
文档格式:PDF 文档大小:258.01KB 文档页数:14
一、例题精选 【例题22.1】当基本RS触发器的R和S端加上图22.1所示的波形时试画出Q端的输出波形。设初始状态为“0”和“1”两种情况
文档格式:PDF 文档大小:168.79KB 文档页数:7
一、例题精选 【例题5.1】有一电容元件,C=0.5F,今通入一三角波形的周期电流(图5.1(b),(1)求电容元件两端电压uc;(2)作出u波形;(3)计算t=2.5s时电容元件的电场中储存的能量。设uco=0
文档格式:PDF 文档大小:206.83KB 文档页数:7
Handout 7: Lag and PI compensation Eric Feron Lag Compensation goals: Raise gain at low frequencies while leaving rossover &z higher frequencies untouched b≥0. When b=0: Add an integrator in the loop Typical lag Bode Plot
文档格式:PDF 文档大小:109.88KB 文档页数:4
测1.1现有两种说法:①塑性材料中若某点的最大拉应力mx=s,则该点一定会产生屈 服;②脆性材料中若某点的最大拉应力max=0b,则该点一定会产生断裂,根据第
文档格式:PDF 文档大小:64.77KB 文档页数:3
1.氧气钢瓶内的容积为40.0L,压力为1.01Mpa,室温27℃。求钢瓶中尚有氧气的质量为多少克。 2.在容积为50L的容器中,含有140g的CO和0g的H2,温度为300K试计算: (1)CO与H2的分压;(2)混合气的总压
文档格式:PDF 文档大小:151.99KB 文档页数:8
1 Induction Recall the principle of induction: Principle of Induction. Let P(n) be a predicate. If ·P(0) is true,an for all nE N, P(n) implies P(n+1), then P(n) is true for all nE N As an example let's try to find a simple expression equal to the following sum and then use induction to prove our guess correct 1·2+2·3+3:4+…+n·(mn+1) To help find an equivalent expression, we could try evaluating the sum for some small n and(with the help of a computer) some larger n sum
文档格式:PDF 文档大小:224.79KB 文档页数:11
1 The Number-Picking Game Here is a game that you and I could play that reveals a strange property of expectation. 3, First, you think of a probability density function on the natural numbers. Your distri- bution can be absolutely anything you like. For example, you might choose a uniform distribution on 1, 2, ... 6, like the outcome of a fair die roll. Or you might choose a bi- probability, provided that,...,n. You can even give every natural number a non-zero nomial distribution on 0, 1 he sum of all probabilities is 1
文档格式:PDF 文档大小:34.07KB 文档页数:4
一、判断题:试判断对错,并写出原因或相应的公式(2分×5=10分) 1.熵增原理的表达式为:△S≥0() 2.二阶舍项维里方程可用于计算纯物质的逸度系数()
文档格式:PDF 文档大小:397.78KB 文档页数:20
Before we look specifically at thin-walled sections, let us consider the general case (i.e, thick-Walled) Hollow thick-walled sections Figure 12.1 Representation of a general thick-walled cross-section 中=c2 on one boundary φ=c1 on one boundary This has more than one boundary(multiply-connected do=0 on each boundary
文档格式:PDF 文档大小:137.57KB 文档页数:4
1.设μ是环上的有限可加测度,即μ是R上的非负值集函数满足μ()=0 和有限可加性.证明若μ满足次可数可加性,则μ是上的测度 2.设A是X的一个非空真子集.试在-代数={,X,A,A}上定义一个不 恒为零的有限测度
首页上页7677787980818283下页末页
热门关键字
搜索一下,找到相关课件或文库资源 983 个  
©2008-现在 cucdc.com 高等教育资讯网 版权所有