A cargo shipper and the underwriter requested to insure a maritime risk requie some assurance that any particular vessel is structurally fit to undertake a proposed voyage.TO enable the shipper and underwriter to distinguish the good risk from the bad2a system of classification

0-1已知a=127+4m,b=-10m,试分别用作图法和解析法求解:(1)a+b:(2)a-b。 解:(1)a+b=(127+47-101)m=(27+4万)

Nucleophile Substitutionen an Carbonsaurederivaten 6-A1 Pivalinsaurepyrrolidid aus Pivaloylchlorid und Pyrrolidin 6-A2 tert-Butylcyclohexenylketon aus Pivalinsaurepyrrolidid (6-A1) und dem von 1- Bromcyclohexen (4-A3) abgeleiteten Grignard-Reagenz

1.(01-1-03)设矩阵A满足A2+A-4E=O,其中E为单位矩阵,则(A-E)-1= 解应填(A+2E) 应设法分解出A-E因子.由A2+A-4E=O,有 (-)(a+2e)=2e,即(a-e)-(a+2e)=e

1.向量:n个数a1,a2,,an构成的有序数组,记作a=(a1,a2,,an), 称为n维行向量 a;称为向量a的第i个分量 a∈R一称a为实向量(下面主要讨论实向量) a;∈C称a为复向量 零向量:θ=(0,0,…,0)

4.1向量及其运算 1.向量:n个数a1,a2,an构成的有序数组,记作a=(a1,a2,an), 称为n维行向量 a称为向量a的第i个分量 a;∈R称a为实向量(下面主要讨论实向量) a∈C称a为复向量

4.2.2子空间的交与和,生成元集 定义4.13设a1,a2,,a,∈V,则{ka1+k2a2++ka,k∈K,i=12}是V的 一个子空间,称为由a1,a2,,a,生成的子空间,记为(aa2,,a)易见,生成的子 空间的维数等于a1,a2,…,a的秩

第三章3-3行列式的初步应用 3.3.1行列式的应用:用行列式求逆矩阵;克莱姆法则 定义设矩阵 a1a12…an A= a21a22…a an1an2…a 矩阵 . A12A22An2 : AnA2n…A 称为A的伴随矩阵。 由行列式的性质容易证得

1 Neglect: A Disorder of Spatial Attention 1 Anjan Chatterjee 2 Bálint’s Syndrome: A Disorder of Visual Cognition 27 Robert Rafal 3 Amnesia: A Disorder of Episodic Memory 41 Michael S. Mega 4 Semantic Dementia: A Disorder of Semantic Memory 67 John R. Hodges 5 Topographical Disorientation: A Disorder of Way-Finding Ability 89 Geoffrey K. Aguirre 6 Acquired Dyslexia: A Disorder of Reading 109 H. Branch Coslett 7 Acalculia: A Disorder of Numerical Cognition 129 Darren R. Gitelman 8 Transcortical Motor Aphasia: A Disorder of Language Production 165 Michael P. Alexander 9 Wernicke Aphasia: A Disorder of Central Language Processing 175 Jeffrey R. Binder 10 Apraxia: A Disorder of Motor Control 239 Scott Grafton 11 Lateral Prefrontal Syndrome: A Disorder of Executive Control 259 Robert T. Knight and Mark D’Esposito Contributors 281