如果函数x=f(y)在某区间内单调、可导且f(y)≠0,那么 它的反函数y=f(x)在对应区间f(1)内也可导,并且

9-1试求下列函数的拉普拉斯象函数: (1) f()= sinh ate(t) (2)f(t)=2(t-1)-3e(t) (3)f(t)=e(t)+2(t-)e-)+38(t-2); (4)f(t)=t[e(t-1)-g(t-2

then there exists AE R\ such that (Kuhn-Tucker condition) G(s') =0 and 1. Lagrange Method for Constrained Optimization FOC: D.L(,\)=0. The following classical theorem is from Takayama(1993, p.114). Theorem A-4 (Sufficieney). Let f and, i= ,..m, be quasi-concave, where Theorem A-1. (Lagrange). For f: and G\\, consider the following G=(.8 ) Let r' satisfy the Kuhn-Tucker condition and the FOC for (A.2). Then, x' problem is a global maximum point if max f() (1)Df(x') =0, and f is locally twice continuously differentiable,or

1.NH4HS(s)和任意量的NH3(g)及H2S(g)达平衡时,有: (A)C=2,=2,f=2 (B)C=1,=2,f=1 (C)C=2,=3,f=2 (D)C=3,=2,f=3

.下列函数的极大值点和极小值点: (1)f(x,y) (2)f(x,y)=3axy-x3-y2(a>0) (3)f(x,y) (a,b>0) (4)f(x,y)=e2(x+y2+2y)

一、三重积分的定义 设f(x,y,)是空间有界闭区域Ω上的有界 函数,将闭区域Ω任意分成n个小闭区域△v, △,,△v,其中△v表示第个小闭区域,也表 示它的体积,在每个△v上任取一点(5)作 乘积f(,△v,(i=1,2,n),并作和,如 果当各小闭区域的直径中的最大值λ趋近于零 时,这和式的极限存在,则称此极限为函数 f(x,y,z)在闭区域Ω上的三重积分,记为 f(x, y,), Ω

凸函数定义及其等价形式: 设f(x)在区间I上有定义,若对任意x1、x2∈I,A∈[0,1]成立不等式: f(Ax1+(1-4)x2)≤Af(x1)+(1-λ)f(x2) 则称f(x)是区间I上的凸函数

2.题二图所示为搜索式超外差接收机原理图,其侦察频段为f口f2=10002000MH,中放带宽为4,=2MH。现有载频为1200M,脉冲为lμs的常规雷达脉冲进入接收机 (1)画出频率显示器上画面及信号波形,说明波形包络及宽度与哪些因素有关? (2)中频频率f及本振频率f应取多大,为什么? (3)画出接收机各部分频率关系图

一、选择填空 (x2 1、已知lim-ax-b=0,则( ) x→x+1 (A)a=1,b=1(B)a=-1,b=-1(C)a=-1,b=1(d)a=1b=-1 2、函数f(x)=x(x2-3x+2)(x+2)有()个不可导点。 (A)1(B)2(C)3(D)4 3、设f(x)=x(x-1)(x-2)…(x-2004),则f(0)=() (A)-2003(B)-2004(C)2003(D)2004 4、设f(x)={sin≠0

1 The eigenvalue distribution function For an N × N matrix AN , the eigenvalue distribution function 1 (e.d.f.) F AN (x) is defined as F AN (x) = Number of eigenvalues of AN ≤ x . (1) N As defined, the e.d.f. is right continuous and possibly atomic i.e. with step discontinuities at discrete points. In practical terms, the derivative of (1), referred to as the (eigenvalue) level density, is simply the