1解:△S=KhW=Kn (N-n)l n! F=△E-T△S=△E- KTLn N-ln(N-n)-lnn!] 根据 Stirling公式:当N很大时,hN=NhN-N,将上式整理得 △F=△E- KTINIn N-(N-n)h(N-n)-nhn] 平衡时,自由能具有最小值,由于热缺陷n引起的自由焓的变化()xp=0

1. Asymmetric auctions Consider an interdependent-values auction with two bidders, each of whom observes an i.i.d uniform signal s; E [ 0, 1]. Bidder i' s valuation for the object is equal to

从物理学知道,如果物体在做直线运动的过程中受到常力F作用,并且力F的 方向与物体运动的方向 致,那么,当物体移动了距离s时,力F对物体所作的功是W=F·s如果 物体在运动过程中所受到的力 是变化的,那么就遇到变力对物体作功的问题,下面通过例1说明如何计算变力 所作的功

The principles of application fertilizers Law of the Minimum: the crop's yield is restricted by the lack of one element, even Mg- al Zn S though there may be sufficient quantities of all the

To Examine Procedures Involved in Retail Organization Set Up To Examine Retail Organizational Arrangements To Consider Retailing's Special Human Resource Environment To Describe Principles and Practices of Retailing's Human Resource Management Process

(1)1/0方程:D(p)r(t)=N(p)e(t) (2)系统函数H(s)=(s) (3)框图/流图 (4)状态方程

9-4用基点法求平面图形内各点的加速度 作平面运动的平面图形S, 选A点为基点。其运动可分解为: S 1、随基点的平动一牵连运动

2-1设n个人围坐在一个圆桌周围,现在从第s个人开始报数,数到第m个人,让他出局; 然后从出局的下一个人重新开始报数,数到第m个人,再让他出局,……,如此反复直到 所有的人全部出局为止。下面要解决的 Josephus问题是:对于任意给定的n,s和m,求 出这n个人的出局序列

一、相对论时空结构 1、光锥---间隔分类的几何意义 再论间第一个事件时空坐标(0,0,0,0),第二个事件任意(x,y,zt 则 S2=2t2为空间间隔+y2+z2)r r=ct,s两事件用光信号联系

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