Chapter 14-Learning objectives Differentiate between nonparametric and parametric hypothesis tests Determine when a nonparametric test should be used instead of its parametric counterpart Appropriately apply each of the nonparametric methods introduced o 2002 The Wadsworth Group

The Economics of Public International Law Alan O. Sykes\ Abstract: This paper is a preliminary draft for eventual inclusion in the Handbook of Law and Economics, A. Mitchell Polinsky Steven Shavell editors. It reviews and synthesizes the work of economists and law and economics scholars in the field of public international law. The bulk of that work has been in the area of international trade, but many of the ideas in the trade literature have implications for other subfields

金绿宝石(Chrysoberyl) 1、主要特征 成分:BeAl2O4 晶系:斜方,二轴晶,正光性(+)

随着生物技术的发展和不断完善,许多研究者试图通过生物技术的方法来获得雄性 不育。如鼬riai竽,o:tw等,Li等分别将白喉毒素和两个不同的核糖核酸 酶(Ra18和rmse基因进行融合,通过含抗除草剂基因的植物双元表达载体转 化烟草,得到转基因雄性不育烟草和油菜(再如 Schuiling等将农杆:ines 的N间的rolc基因与35启动子串联成嵌合基因转化烟草

O Copyright 2006 SAP AG. All rights reserved IBM, DB2, DB2 Universal Database, OS/2, Parallel Sysplex, MVS/ESA, AIX, S/390, AS/400, OS/90, OS/400, iSeries, PSeries, xSeries, zSeries, The information in this document is proprietary and contains z/OS, AFP, Intelligent Miner, WebSphere, Netfinity, Tivoli, Informix

羰基配合物中金属可以是零价甚至是负价。 为什么零价甚至是负价的金属原子能与配体 CO结合形成稳定的羰基配合物呢? o-n键 金属与CO间的-键是如何形成的呢?

一、选择填空题(将正确答案的字母填入括号内,每小题只不过一个正确答案,多填无分,本题共36分,每小题2分) 1.下列分子或离子中,不含有孤对电子的是() (A)NH (B)H2O (C)H2S (D) NH2

生物代谢是指生物活体与外界环境不断进行的 物质(包括气体、液体和固体)交换过程。 ·合成代谢一般是指将简单的小分子物质转变成 复杂的大分子物质的过程。分解代谢则是将复 杂的大分子物质转变成小分子物质的过程。 ·糖、脂和蛋白质的合成代谢途径各不相同,但 是它们的分解代谢途径则有共同之处,即糖、 脂和蛋白质经过一系列分解反应后都生成了酮 酸并进入三羧酸循环,最后被氧化成CO2和H2O

10.1 概述 烃化指的是在有机分子中的碳硅氮磷氧和硫等原子上引入烃基的总称。本章只讨论N-烃化、O-烃化和C-烃化。 10.2 N-烃化 有机分子中氨基上氢原子被烃基取代的反应叫N-烃化。 1）用醇类的N-烷化 醇类是弱烷化剂，芳胺的碱性也较弱，要求相当高的反应温度。 液相高压N-烷化一般用酸性催化剂如浓硫酸等。 气固相接触催化N-烷化的关键是催化剂的筛选

pH of a buffer and buffer capacity Example: For a buffer solution consisting of 0. 1 M acetic acid and o1M sodium acetate the ph of the solution is 4.75 HAc= i If an amount of hydrochloric acid equivalent to 10% of the acetate present, is added to the buffer, what is the new pH of the solution?